216^x-1=6
To determine the food received by Plant 1, first calculate Plant 2's food based on Plant 3's amount (30 grams * 3/5), yielding 18 grams. Then, subtract 10 grams (because Plant 1 gets 10 grams less than Plant 2) to find that Plant 1 gets 8 grams of food.
To solve this problem, we start by finding out how much food Plant 2 receives. Since Plant 2 gets 3/5 of the food that Plant 3 receives, and we know that Plant 3 gets 30 grams, we find out Plant 2's food amount by doing a multiplication of 30*(3/5), giving us 18 grams.
Next, we need to consider how much Plant 1 receives in comparison to Plant 2. The problem states Plant 1 gets 10 grams less than Plant 2. So, if Plant 2 receives 18 grams, then Plant 1 must receive 18 - 10 = 8 grams.
Plant 1 receives 8 grams of food based on the data provided in the problem.
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This question is based on the system of equation. Therefore, the 8 litres of the 20% and 7 liters of the 50% solution.
Given:
A chemist needs to mix an 20% acid solution with a 50% acid solution to obtain 15 liters of a 34% acid solution.
We need to determined the numbers of liters of each of the acid solutions must be used.
According to the question,
Let the number of liters be x for 20% and y for the 50% solution.
Then,
⇒ 0.2x + 0.5y = 15 0.34
⇒ 0.2x + 0.5y = 5.1
Also we have:
Multiply the first equation by -2:
⇒ x + y = 15
Adding these last 2 equations:
⇒ -0.4x - y = -10.2
⇒ 0.6x = 4.8
⇒ x = 4.8 / 0.6
⇒ x = 8 and y = 15 - 8 = 7 .
Therefore, the 8 liters of the 20% and 7 liters of the 50% solution acid solutions must be used.
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Answer:
8 litres of the 20% and
7 litres of the 50% solution.
Step-by-step explanation:
Let the number of litres be x for 20% and y for the 50% solution. Then
0.2x + 0.5y = 15*0.34
0.2x + 0.5y = 5.1 Also we have:
x + y = 15 Multiply the first equation by -2:
-0.4x - y = -10.2 Adding these last 2 equations:
0.6x = 4.8
x = 4.8 / 0.6
x = 8.
and y = 15 - 8 = 7 .
Answer:
Wow that's impressive he can type 4 letters a second and 240 a minute
In your answer, please explain and show your work to the best of your ability. I want to know how you got your answer. It will help me a lot! :)
Note: These questions are from 7-3 Practice: Rational Exponents from Glencoe Algebra 1.
Good luck! :)
To find the distance fallen, substitute the given velocity into the equation and solve for h. To find the power being used, substitute the given current and resistance into the equation and solve for P.
1. To find the distance that an object has fallen if its velocity is 96 feet per second, we need to use the given equation v = 8h^(1/2). We'll substitute 96 for v in the equation and solve for h:
96 = 8h^(1/2)
To isolate h, we'll divide both sides of the equation by 8:
12 = h^(1/2)
To get rid of the exponent, we'll square both sides of the equation:
144 = h
Therefore, the object has fallen a distance of 144 feet.
2. The equation IR^(1/2) = √P represents the relationship between current (I), power (P), and resistance (R). We're given that I = 2.5 amps and R = 16 ohms. We'll substitute these values into the equation and solve for P:
(2.5)(16)^(1/2) = √P
(2.5)(4) = √P
10 = √P
To isolate P, we'll square both sides of the equation:
100 = P
Therefore, the appliance is using 100 watts of power.
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