Introductory Astronomy1. Light is absorbed and emitted in the form ofwhich are "packets" ofelectromagnetic radiation that carry a specific amount of energy.photonsionsexcited atomsprotons2. Light is characterized by which two properties? point)electromagnetic energy and wavelengthwavelength and frequencyfrequency and radiationOelectromagnetic radiation and gamma rays
Introductory Astronomy1. Light is absorbed and emitted in the form - 1

Answers

Answer 1
Answer: Light ... and all other forms of electromagnetic radiation ... behaves
as if it were a stream of 'packets' that we call 'photons', each one
carrying a specific amount of energy.

Light  ... and all other forms of electromagnetic radiation ... is
characterized by its wavelength.  That is, once you state its wavelength,
you've stated everything there is to know about the light, including its
frequency, and the energy carried by each photon. 

Related Questions

Whate type of wave is made up of a sine wave plus all of its odd harmonics?
What role does energy play when an object is not moving?
Sound waves can't travel through A. an elastic material.B. a liquid.(C. a solid.)D. a vacuum.I answered C and it's not correct so i dont know what else it could be please help
1. What is the bond angle between the hydrogen atoms in an ammonia (NH3) molecule? 2. What is the bond angle between the oxygen atoms in the carbon dioxide molecule? 3. What is the molecular geometry of a methane (CH4) molecule?
In 2005, the space probe Deep Impact launched a 370 kg projectile into Comet Temple 1. Observing the collision helped scientists learn about the comet’s characteristics. The comet is estimated to have a mass of about 9.0 x 10^13 kg.a. Assuming the estimated mass of the comet at that time was correct, at what distance from the comet’s centre was the gravitational force between the comet and the projectile 32 N? b. Deep Impact also released a probe to fly by the comet and record images of the collision. Determine the strength of the comet’s gravitational field at the probe’s distance of 5.0 x 103 km from the comet.

In the diagram, the liquid is vaporizing at which point? Question 5 options: A
B
C
D
E

Answers

Answer : The correct option is, (D)

Explanation :

Vaporization process : It is type of process which occurs when phase changes from liquid phase to gaseous phase at constant temperature. And liquid converted to gas phase at temperature 100^oC.

Melting process : It is type of process which occurs when phase changes from solid phase to liquid phase at constant temperature. And solid converted to liquid phase at temperature 0^oC.

In the given diagram,

'A' shows the solid phase, 'B' shows the melting process, 'C' shows the liquid phase, 'D' shows the vaporization process and 'E' shows the gas phase.

Hence, the liquid is vaporizing at 'D' point.

I really think it's C,D,& E because the boiling point had passed to make the water starts to boil

An electron is released from rest at the negative plate of a parallel plate capacitor. The charge per unit area on each plate is = 2.5 x 10⁻⁷ C/m², and the plates are separated by a distance of 1.7 x 10⁻² m. How fast is the electron moving just before it reaches the positive plate?

Answers

The speed of the electron before reaching the positive plate is 1.30 * 10^(7)\ m / s

Explanation:

As per Gauss law of electro statistics, the electric field generated by a capacitor is directly proportional to the surface charge density of the plate and inversely proportional to the dielectric constant. In simple words, the electric field is proportional to the surface charge density.  So,  

    \text {Electric field}=(\sigma)/(\varepsilon_(0))

And then from the second law of motion, F=m * acceleration

So acceleration exerted by the electrons will be directly proportional to the force exerted on them and inversely proportional to the mass of the electron.

        Acceleration =(F)/(m)

Since force is also calculated as product of charge with electric field in electrostatic force,

       \text {Acceleration}=(q E)/(m)=(q \sigma)/(m \varepsilon_(0))

So, the charge of electronq=1.6 * 10^(-19)\ \mathrm{C}, \sigma=\text { Charge per unit area }=2.5 * 10^(-7)\ \mathrm{C} / \mathrm{m}^(2)

m is the mass of electron which is equal to 9.11 * 10^(-31)\ \mathrm{kg}

\varepsilon_(0)=8.85 * 10^(-12)\ \mathrm{Nm}^(2) \mathrm{C}^(-2)

Then,

    \text { Acceleration }=(1.6 * 2.5 * 10^(-19) * 10^(-7))/(9.11 * 8.85 * 10^(-31) * 10^(-12))=(4 * 10^(-19-7))/(80.62 * 10^(-31-12))

   \text { Acceleration }=0.0496 * 10^(-19-7+31+12)=0.0496 * 10^(17)\ \mathrm{m} / \mathrm{s}^(2)

So the acceleration of the electron in the capacitor will be 4.96 * 10^(15) m / s^(2)

Then, the velocity can be observed from the third equation of motion.

    v^(2)=u^(2)+2 a s

As u = 0 and s is the distance of separation between two plates.

   \begin{array}{c}v^(2)=0+\left(2 * 4.96 * 10^(15) * 1.7 * 10^(-2)\right) \nv^(2)=16.864 * 10^(15-2)=16.864 * 10^(13)=1.684 * 10^(14)\end{array}

Thus, v=\sqrt{\left(1.68 * 10^(14)\right)}=1.30 * 10^(7)\ m/s

So, the speed of the electron before reaching the positive plate is 1.30 * 10^(7) \mathrm{m} / \mathrm{s}.

How is the resistor of a 40v lamp higher then the resistor of a 60v lamp?

Answers

Power dissipation = (voltage across the component)² / (resistance of the component)

Since the resistance is in the denominator of the fraction in this formula for the
quantity of power dissipated, you can see that when the supply voltage is constant,
the smaller resistance dissipates more power.

So the 40w lamp has higher resistance than the 60w bulb.

A snail crawls 300 cm in 1 hour. Calculate the snail's speed in each of the following units. A) cm/h B) cm/min C) m/h

Answers

A) 300cm/h
B)1 hr=60 min
300/60=5
5cm/min
C)1m=100cm
300/100=3
3m/h

An automobile having a mass of 2000 kg deflects its suspension springs 0.02 m under static conditions. Determine the nafural frequency of the automobile in the vertical direction by assuming damping to be negligible.

Answers

The natural frequency of the automobile in the vertical direction is 3.52 Hertz

Static equilibrium

Static equilibrium refers to the physical state in which the components of a system are at rest and the net force acting through the system is equal to zero.

In static equilibrium:

kd = mg

where;

k = effective spring constant of the spring.

mg = the weight of the car

d = static deflection.

also K = mω²

where ω is angular velocity

m is mass

Thus, mω²d = mg

ω²d = g

ω = √g/d

ω = g/d

ω  = √9.8/0.02

ω = 22.15 rad/sec

Converting to Hertz unit for frequency

1 rad/s = 0.1591 Hertz

22.14 rad/s = 22.14 * 0.1591

22.14 rad/s = 3.525 hertz

Therefore, the natural frequency of the automobile in the vertical direction is 3.52 Hertz

Learn more about natural frequency at: brainly.com/question/11753773

Answer:Frequency = 3.525 Hertz

Explanation:In static equilibrium, kd =mg

Where k= effective spring constant of the spring.

mg= The weight of the car.

d= static deflection.

Therefore, w =SQRTg/d

w = SQRT 9.81/0.02

w= 22.15 rad/sec

Converting to Hertz unit for frequency

1 rad/s = 0.1591

22.15rad/s=?

22.15 × 0.1591= 3.525 hertz

The total potential and kinetic energy of all the microscopic particles in an object make up itsa. nuclear energy.
b. chemical energy.
c. electric energy.
d. thermal energy.

Answers

b. chemical energy
because thats the only way i see it out of your anwser choices hope i helped