The magnitude of the force F on the 1.0 nC charge 3.11N.
A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
In this problem, the 2.0 nC charges both act forces of equal magnitude on the 1.0 nC charge. Since there x-components are equal but opposite, they cancel out and only the y-components remain and add up. This can be used then to calculate for the magnitude of the total electrostatic force.
F = 2 * q1 * q2 / 4 / pi / eps_0 / r^2 * sqrt(3) / 2
F = 2 * 1.0e-9 * 2.0e-9 / 4 / pi / 8.854e-12 / (1.0e-2)^2 * sqrt(3) / 2
F = 3.11N
The magnitude of the force F on the 1.0 nC charge 3.11N.
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Answer:
11.11 s
Explanation:
Given:
u = 80 km/h = 22.22 m/s
v = 160 km/h = 44.44 m/s
a = 2.0 m/s²
Find: t
v = u + at
44.44 m/s = 22.22 m/s + (2.0 m/s²) t
t = 11.11 s