Consider the following functions. f(x) = x − 3, g(x) = x2 Find (f + g)(x). Find the domain of (f + g)(x). (Enter your answer using interval notation.) Find (f − g)(x). Find the domain of (f − g)(x). (Enter your answer using interval notation.) Find (fg)(x). Find the domain of (fg)(x). (Enter your answer using interval notation.) Find f g (x). Find the domain of f g (x). (Enter your answer using interval notation.)

Answers

Answer 1
Answer:

Answer:

(f+g)(x)=x-3+x^2 ; Domain = (-∞, ∞)

(f-g)(x)=x-3-x^2 ; Domain = (-∞, ∞)

(fg)(x)=x^3-3x^2 ; Domain = (-∞, ∞)

((f)/(g))(x)=(x-3)/(x^2) ; Domain = (-∞,0)∪(0, ∞)

Step-by-step explanation:

The given functions are

f(x)=x-3

g(x)=x^2

1.

(f+g)(x)=f(x)+g(x)

Substitute the values of the given functions.

(f+g)(x)=(x-3)+x^2

(f+g)(x)=x-3+x^2

The function (f+g)(x)=x-3+x^2 is a polynomial which is defined for all real values x.

Domain of (f+g)(x) = (-∞, ∞)

2.

(f-g)(x)=f(x)-g(x)

Substitute the values of the given functions.

(f-g)(x)=(x-3)-x^2

(f-g)(x)=x-3-x^2

The function (f-g)(x)=x-3-x^2 is a polynomial which is defined for all real values x.

Domain of (f-g)(x) = (-∞, ∞)

3.

(fg)(x)=f(x)g(x)

Substitute the values of the given functions.

(fg)(x)=(x-3)x^2

(fg)(x)=x^3-3x^2

The function (fg)(x)=x^3-3x^2 is a polynomial which is defined for all real values x.

Domain of (fg)(x) = (-∞, ∞)

4.

((f)/(g))(x)=(f(x))/(g(x))

Substitute the values of the given functions.

((f)/(g))(x)=(x-3)/(x^2)

The function ((f)/(g))(x)=(x-3)/(x^2) is a rational function which is defined for all real values x except 0.

Domain of (f/g)(x) = (-∞,0)∪(0, ∞)

Answer 2
Answer:

(f + g)(x) = x^2 + x - 3, domain: all real numbers.

(f - g)(x) = -x^2 + x - 3, domain: all real numbers.

(fg)(x) = x^3 - 3x^2, domain: all real numbers.

f(g(x)) = x^2 - 3, domain: all real numbers.

To find (f + g)(x), we need to add the functions f(x) and g(x).

The function f(x) = x - 3 and the function g(x) = x^2.

So, (f + g)(x) = f(x) + g(x) = (x - 3) + (x^2).

Expanding this equation, we get (f + g)(x) = x^2 + x - 3.

To find the domain of (f + g)(x), we need to consider the domain of the individual functions f(x) and g(x).

Since both f(x) = x - 3 and g(x) = x^2 are defined for all real numbers, the domain of (f + g)(x) is also all real numbers.

To find (f - g)(x), we need to subtract the function g(x) from f(x).

So, (f - g)(x) = f(x) - g(x) = (x - 3) - (x^2).

Expanding this equation, we get (f - g)(x) = -x^2 + x - 3.

The domain of (f - g)(x) is also all real numbers, since both f(x) and g(x) are defined for all real numbers.

To find (fg)(x), we need to multiply the functions f(x) and g(x).

So, (fg)(x) = f(x) * g(x) = (x - 3) * (x^2).

Expanding this equation, we get (fg)(x) = x^3 - 3x^2.

The domain of (fg)(x) is all real numbers, since both f(x) and g(x) are defined for all real numbers.

To find f(g(x)), we need to substitute g(x) into the function f(x).

So, f(g(x)) = f(x^2) = x^2 - 3.

The domain of f(g(x)) is also all real numbers, as g(x) = x^2 is defined for all real numbers, and f(x) = x - 3 is defined for all real numbers.

In summary:

- (f + g)(x) = x^2 + x - 3, domain: all real numbers.

- (f - g)(x) = -x^2 + x - 3, domain: all real numbers.

- (fg)(x) = x^3 - 3x^2, domain: all real numbers.

- f(g(x)) = x^2 - 3, domain: all real numbers.

To Learn more about real numbers here:

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What is the solution of the system of equationsy-x=5 and y=x² +5?
1) (0,5) and (1,6)
2) (0,5) and (-1,0)
3) (2.9) and (-1,4)
4) (-2,9) and (-1.4)

Answers

You can basically just plug in the values. “1) (0,5) and (1,6)” is correct.

In a survey of a community, it was found that 85% of the people like winter season and 65% like summer season. If none of them did not like both seasonsi) what percent like both the seasons

Answers

Answer:

50%

Step-by-step explanation:

Let :

Winter = W

Summer = S

P(W) = 0.85

P(S) = 0.65

Recall:

P(W u S) = p(W) + p(S) - p(W n S)

Since, none of them did not like both seasons, P(W u S) = 1

Hence,

1 = 0.85 + 0.65 - p(both)

p(both) = 0.85 + 0.65 - 1

p(both) = 1.50 - 1

p(both) = 0.5

Hence percentage who like both = 0.5 * 100% = 50%

You are measuring the height of a statue. You stand 17 feet from the base of the statue. You measure the angle of elevation from the ground to the top of the statue to be 61º. Find the height h of the statue to the nearest foot.

Answers

Answer:

  31 ft

Step-by-step explanation:

The statue represents the side of a right triangle that is opposite the angle of elevation. The distance to the statue represents the side adjacent to the angle. Then ...

  Tan = Opposite/Adjacent

  tan(61°) = h/(17 ft)

Multiplying by 17 ft, we have ...

  h = (17 ft)tan(61°) ≈ 30.67 ft

  h ≈ 31 feet

Square root of -61 to the nearest tenth

Answers

Answer:

7.8 i

Step-by-step explanation:

Since -61 is negative, you simply do the square root of positive 61 and add an i (imaginary) so signify that it's negative.

A vase in the shape of a cube measures 8 Inches on each side. The vase is half full with water. How many cubic inches of water are in the vase?

Answers

There are 256 cubic inches of water in the vase.

How many cubic inches of water are in the vase?

We know that the volume of a cube with side length S is:

V = S^3

In this case, we know that S = 8in, then the volume is:

V = (8 in)^3 = 512 in^3

And we know that it is half full with water, so the volume of water in the vase is:

V' = (512 in^3)/2 = 256 in^3

If you want to learn more about volume, you can read:

brainly.com/question/1972490

Answer:

256

Step-by-step explanation:

First find the volume of the cube, which is 8^3, or 512. Half of that is how much water there is, which is 256 in^3.

A candy company is designing the packaging for its new candy bar. The bars will be packed in cartons which are 1 foot wide, 1 foot high, and 1 foot long. How many of these cartons can they pack into the shipping crate which is 5 ft long, 12 ft wide, and 4 ft high?show your work.

Answers

Answer:

240 cartons

Step-by-step explanation:

If the bars will be packed in cartons which are 1 foot wide, 1 foot high, and 1 foot long, the volume of the carton will be expressed as shown;

Volume of carton = Length * Breadth * Height

Volume of carton = 1ft*1ft*1ft

= 1ft³

Given the dimension of shipping crate to be 5 ft long, 12 ft wide, and 4 ft high, the volume of the tank will be 5*12*4 = 240ft³

Number of cartons they pack into the shipping crate = Volume of the shipping crate/volume of one carton

Number of cartons they pack into the shipping crate = 240ft³/1ft³

= 240 cartons

Answer:

number of cartons that can be packed in the shipping crate = 240 cartons

Step-by-step explanation:

The cartons are cube since the face all have the same dimension . The length = 1 ft, width = 1 ft and height = 1 ft.

The shipping crate is a rectangular prism or cuboid . The dimension is given as follows.

length = 5 ft

width = 12 ft

height = 4 ft

The number of the cartons that can be packed in the shipping crate can be calculated as follows.

volume of the cubed carton = L³

where

L = length

volume of the cubed carton = 1³ = 1 ft³

Volume of the shipping crate = LWH

where

L = length

W = width

H = height

Volume of the shipping crate = 5 × 12 × 4

Volume of the shipping crate = 240  ft³

number of cartons that can be packed in the shipping crate = 240/1 = 240 cartons