Replace f(x) with 0 and solve for x. We do this because the x intercepts always occur when y = 0. Keep in mind that y = f(x).
f(x)=x^3-9x^2+20x
0=x^3-9x^2+20x
x^3-9x^2+20x = 0
x(x^2-9x+20) = 0 .... factor out GCF x
x(x-5)(x-4) = 0 ... factor the stuff inside
x = 0 or x-5 = 0 or x-4 = 0 ... zero product property
x = 0 or x = 5 or x = 4
It takes 3 days until the value becomes zero when you triple 4 and subtract 2 each day.
Let "d" be the number of days, and "x" be the value at the end of each day.
On the first day, "x" starts at 4, and then it's reduced by 2 each day. So, the value at the end of each day can be represented as:
Day 1: x = 4
Day 2: x = 4 - 2 = 2
Day 3: x = 2 - 2 = 0
As we can see, on Day 3, the value becomes zero.
Therefore, it takes 3 days until the value becomes zero when you triple 4 and subtract 2 each day.
To know more about zero:
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what is this answer ?
Answer:
44x/5
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