CHEMISTRY MIDDLE SCHOOL

A 50°C solution has a pH of 3.30. At this temperature, Kw = 5.48 x 10 9. What is the pOH of the solution?

Answers

Answer 1
Answer:

Answer:

9.93

Explanation:

Your value for Kw is incorrect. The correct value is 5.48 × 10^-14.

  pH + pOH = pKw

3.30 + pOH = -log(5.84 × 10^-14) = 13.23

          pOH = 13.23 - 3.30 = 9.93

The pOH of the solution is 9.93.
Answer 2
Answer:

The pOH of the solution is 10 .

Given that, the pH of the solution is 3.30, we also know that;

pH = - log[H^+]

Hence;

[H^+] = Antilog (-3.3)

[H^+] = 5.0 × 10^-4 M

But;

Kw = [H^+] [OH^-]

[OH^-] = Kw/[H^+]

The accurate value of Kw is 5.48 × 10^-14 not  5.48 x 10 9

[OH^-] = 5.48 x 10^-14/ 5.0 × 10^-4

[OH^-] = 1.1 x 10^-10 M

pOH = - log[1.1 x 10^-10 M]

pOH = 10

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By a series of vibrations produced by an object. When an object produces sound, the sound waves travel and reach the ears. :)
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Change 32L of carbon dioxide into moles of carbon dioxide

Answers

32L —> 32000g —> 727.116 Moles (rounded)

Hemoglobin is the protein responsible for transporting O2 throughout the body. Each molecule of hemoglobin combines with four molecules of O2. If 1.22 g of hemoglobin combines with 1.53 mL of O2 at 37 °C and 743 torr, what is the molar mass of hemoglobin based on this experiment?

Answers

Answer:

you correct answer is o27°c3

Answer:

0.27

Explanation:

Using enthalpies of formation, calculate H.

Answers

ΔH° = -851.5 kJ/mol given that

\begin{array}{cc}\textbf{Species}&{\bf {\Delta H_f\textdegree{}}}\n \text{Fe}_2\text{O}_3\;(s) & -824.2\;\text{kJ}\cdot\text{mol}^(-1)\n\text{Al}_2\text{O}_3\;(s) & -1675.7\;\text{kJ}\cdot\text{mol}^(-1)\end{array}

(Source: Chemistry Libretexts.)

Explanation

Refer to a thermodynamic data table for the standard enthalpy of formation for each species.

Don't be alerted if the data for Al (s) and Fe (s) are missing. Why?

  • The standard enthalpy of formation of a substance measures the ΔH required to form each mole of it from the most stable allotrope of its elements under STP.
  • Both Al (s) and Fe (s) are already the most stable form of their element under STP (note that the state symbol matters.) There's no need to form them again.

As a result, \Delta H_f\textdegree{} = 0 for both Al (s) and Fe (s).

\displaystyle \Delta H_{\text{rxn}}\textdegree{} = \text{Sum of }\Delta H\text{ for all }\textbf{Product} - \text{Sum of }\Delta H\text{ for all }\textbf{Reactant}}\n\phantom{\Delta H_{\text{rxn}}\textdegree{}} = (1* \Delta H_f\textdegree{}(\text{Al}_2\text{O}_3\;(s)) + 1* \Delta H_f\textdegree{}(\text{Al}\;(s)) \n \phantom{\Delta H_{\text{rxn}}\textdegree{}=}-(1* \Delta H_f\textdegree{}(\text{Fe}_2\text{O}_3\;(s)) + 1*\Delta H_f\textdegree{}(\text{Fe}\;(s))

\Delta H_{\text{rxn}}\textdegree{}} = (1 * (-1675.7)) - (1*(-824.2)) = -851.5\;\text{kJ}\cdot\text{mol}^(-1).

The number "1" here emphasizes that in case there are more than one mole of any species in one mole of the reaction, it will be necessary to multiply the \Delta H_f\textdegree{} of that species with its coefficient in the equation.

Write a balanced chemical equation for the reaction of solid strontium with fluorine gas.

Answers

Answer:

Sr(s) + F₂(g) → SrF₂(s)

Explanation:

  • A balanced equation is an equation that has an equal number of atoms of elements on either side of the equation.
  • Chemical equations are balanced to obey the law of conservation of mass which states that the mass of reactants and that of the product should always be equal in chemical reactions.
  • Therefore, the balanced chemical equation for the reaction between Sr and F₂ is given by;

Sr(s) + F₂(g) → SrF₂(s)

  • Each side of the equation has 1 atom of Sr and two atoms of F thus the equation is balanced.

Final answer:

Solid Strontium reacts with Fluorine gas in a synthesis reaction to form Strontium Fluoride. The balanced chemical equation is Sr (s) + F2 (g) -> SrF2 (s).

Explanation:

The reaction of solid strontium (Sr) with fluorine gas (F2) is a synthesis reaction, and it forms strontium fluoride (SrF2). The balanced chemical equation for this reaction is:

Sr (s) + F2 (g) → SrF2 (s)

In this equation, 's' stands for solid, 'g' stands for gas, and the arrow ( → ) indicates the direction of the reaction from reactants to products.

Learn more about Balanced Chemical Equation here:

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What is the color of the indicator thymol blue in a solution that has a pH of 11?(1) red (3) pink

(2) blue (4) yellow

Answers

Answer is (2) - blue.


Thymol blue is a pH indicator which 3 colors according to the pH.


Thymol blue shows red color at below pH than 1.2 and shows yellow color at the pH between 2.8 and 8.0. For the pH above 9.6, thymol blue shows blue color.


Hence, the thymol blue has 2 pH ranges as 1.2 - 2.8 and 8.0 - 9.6.


Since, pH = 11 is above the pH = 9.6, thymol blue shows blue color.
The answer would be blue. This is because red indicates 1-2, pink is 3, and yellow is 6.
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