What is the area of parallelogram ABCD?
____ square units
Answers
Answer:
13
Step-by-step explanation:
Here's a method of finding the area of any polygon knowing its vertices. I'm using this parallelogram as an example.
Make a table like this (each vertex with its x- and y-coordinates):
Pt x y
A 3 6
B 6 5
C 5 1
D 2 2
A 3 6
Now multiply each x-coordinate by the y-coordinate on the line below and write it on the right side. Bold type shows the first multiplication.
x y
A 3 6
B 6 5 15
C 5 1 6
D 2 2 10
A 3 6 12
Now multiply each y-coordinate by the x-coordinate on the line below and subtract from each produce you already have. Do each subtraction. Bold type shows the first multiplication.
x y
A 3 6
B 6 5 15 - 36 = -21
C 5 1 6 - 25 = -19
D 2 2 10 - 2 = 8
A 3 6 12 - 6 = 6
Add all the differences.
x y
A 3 6
B 6 5 15 - 36 = -21
C 5 1 6 - 25 = -19
D 2 2 10 - 2 = 8
A 3 6 12 - 6 = 6
+____
-26
The area of the polygon is the absolute value of half of the sum of the differences.
area = |-26/2| = |-13| = 13
Final answer:
You can calculate the area of a parallelogram using the formula: Area = base * height. To do this, you need the length of the base and the perpendicular height of the parallelogram. For example, if the parallelogram has a base of 5 units and a height of 3 units, its area will be 15 square units.
Explanation:
The area of a parallelogram can be calculated with the formula: Area = base * height. In your question, you'll need to know the lengths of base and the height of the parallelogram ABCD to compute the area. It's essential to remember that the height is the perpendicular distance from the base to the top, not the length of the side.
Let's say, for example, the base of your parallelogram is 5 units and the height is 3 units. You would calculate the area as follows: Area = base * height = 5 units * 3 units = 15 square units.
Learn more about Area of Parallelogram here:
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Plz help, I need answers to these questions ASAP, would appreciate a short step-by-step explanation with each! WILL MARK BRAINLIEST!!!You’ve been given $500.00 for your fencing. So first we are going to make as big of a rectangular field as we can with the money that we have for the fencing to surround it. The cost of premium fencing (only the best for your farm, of course) is $11.41 per metre. So with that, and the following equations:A=l*wP=2l+2wWhere A is the area, P is the perimeter, l is the length, and w is the width of a rectangle, we can find the maximum area that we can have for this field.Perimeter of fence:Area of farm:Let’s say we have access to planting 2 different crops, Watermelons and Grapes. We can find the revenue of a crop by the equation:R = (p0 + px)(n0 - nx)Where R is the revenue, p0 is the starting price, n0 is the amount sold at the starting price, p is the price increase, n is the decrease in the amount sold per price increase, and x is the number of price increases.Crop A: Watermelons have a starting price of $12.00 per m2 of area sold. At this price, you can sell 45 m2 worth. For every $2.00 increase, you will sell 1 m2 less. So the first task is to figure out how to put these values into the equation above and turn it into a quadratic function. Then you will need to find the value of x to make the revenue as large as possible. Once you know x, the number of price increases, you can then find what you should price your Watermelons per m2.Equation: R =Number of price increases: x =Price of Watermelon per m^2 =Okay, now we can do the same thing with the grapes, just to give you that extra practice with quadratic functions. The starting price of grapes per m² is $8.00, at which you can sell 60 m² worth. For every $3.00 increase in price, you sell 3 m² less. So use the same method you just used to find the price of grapes per m² of area to maximize revenue.Equation: R =Number of price increases: x =Price of grape per m^2 =Okay, so now, all in all, we have built our farm and found what to price each of our crops at. Now let’s find what amount of each crop to grow and find our profits. Getting right into it, we have the following cost equations:CW = $20.00 * W + $50.00CG = $10.00 * G + $40.00Where CW is the total cost of planting and growing Watermelons, CG is the total cost of planting and growing Grapes, W is the area of Watermelons planted, and G is the area of Grapes planted. Now that we know our cost, we can finally find our profits. Profit is equal to the price per unit area, multiplied by the area sold, subtracted by the total cost planting and growing them, or, Profit = Price * Area - Cost. But at this point, we still don’t know the area of each crop in our field. But we do know a couple of things to figure it out. We know the total area of our farm, found in the first part. Which we can say is, Area = G + W And we were also only given $1590 to plant the crops. So, $1590.00= CW+CG I’ll help you simplify this a bit:$1590.00=$20.00*W+$50.00+$10.00*G+$40.00 $1590.00=$20.00*W+$10.00*G+$90.00So now we have enough information to solve for the areas of Watermelons and Grapes in your field. Here’s some room to do that. Hint: Use either substitution or graph the two equations to find an intersection.Area of watermelon to plant:Area of grapes to pant:Profit of the crops:
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1 kilometer : 10 minutes
That would mean
6 kilometers : 60 minutes
Hope that helps and correct me if I'm wrong!
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After that, you multiply .90 by 84,000 which is $75,600
Another way to do this is to convert 90% to a fraction. To do that, you would put 90/100 which can simplify to 9/10. Then you would multiply that by 84,000. 1 of the 0's can cancel, so you are left with 9x8,400 which gives the same answer
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