Write x^2 − 8x + 13 = 0 in the form (x − a)^2 = b, where a and b are integers.(x − 4)^2 = 3
(x − 3)^2 = 2
(x − 2)^2 = 1
(x − 1)^2 = 4

Can anyone show the steps on how to get the answer?

Answers

Answer 1

Answer: Sure.
The answer is (x-4)^2 = 3

Procedure

Complete a perfect square trinomial to factor:

x^2 - 8x + 13 = 0

Notice that -8x = 2(x)(4)

Given tha x is the square root of x^2, we want to include the square of 4, which is 16.

We must just add 16 to the first two terms, which, of course, obliges to substract the same number to maintain the equality. This way:

(x^2 - 8x + 16) + -16 + 13= 0

Now the three terms in parenthesis can be factor as a binomial squared:

(x - 4)^2 + 13 -16 =0

(x - 4)^2 - 3 = 0

(x - 4)^2 = 3 Which is the answer.

Let me know whether you could follow the explanation.

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Answer:

hi Krystal , I am Felicia

write the equation of the line, in slope- intercept form, that passes through (0,4) and has a slope of -1/2

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y=-1/2x+4 since the slope is -1/2 and the y-int is 4.

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Answer:

Whats the question?

Step-by-step explanation:

What are you asking

23 means 3 · 2

True or false

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False I'm pretty sure buddy

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Answers

The answer is the third one.

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The point of intersection is where the two circles touch each other, and is is (4, 1), because you have to put the x value first.

The equation of the tangent line is just y=4, because it is a straight vertical line.

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