MATHEMATICS HIGH SCHOOL

Find the product.

-a^2 b^2 c^2 (a + b - c)

Answers

Answer 1
Answer: −a^3b^2c^2−a^2b^3c^2+a^2b^2c^3

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Triangle PQR ~ triangle PꞌꞌQꞌꞌRꞌꞌ.Which two transformations were performed on triangle PQR to produce triangle PꞌꞌQꞌꞌRꞌꞌ?

Choose exactly two answers that are correct.


A.Triangle PQR was reflected across the y-axis to produce triangle PꞌQꞌRꞌ.

B.Triangle PQR was reflected across the x-axis to produce triangle PꞌQꞌRꞌ.

C.Triangle PꞌQꞌRꞌ was dilated by a scale factor of to produce triangle PꞌꞌQꞌꞌRꞌꞌ.

D.Triangle PꞌQꞌRꞌ was dilated by a scale factor of 2 to produce triangle PꞌꞌQꞌꞌRꞌꞌ.

Answers

The correct answer for the question that is being presented above is this one: D.Triangle PꞌQꞌRꞌ was dilated by a scale factor of 2 to produce triangle PꞌꞌQꞌꞌRꞌꞌ; C.Triangle PꞌQꞌRꞌ was dilated by a scale factor of to produce triangle PꞌꞌQꞌꞌRꞌꞌ.

Using the formula C = 2πr, find the circumference of a circle with diameter of 28 inches. Round your answer to the nearest inch. A. 88 in. B. 44 in. C. 28 in. D. 56 in.

Answers

the formula given to us relates circumference with radius but we are given diameter instead. good thing we know that diameter is twice the length of radius so if diameter=28, the radius=14. therefore, using our formula, we can find the circumference:
C = 2(pi)(14)
C = 87.96
and this answer is close to 88 so the answer is A

let me know if you have any questions!!!
Hi there! C=πd=π*28=87.96459, 87.96 rounded to the nearest tenth would be 88. Therefore, your answer is A. 88 in

if the measure of angle one is "two-x minus nine" and the measure of angle two is "twenty seven minus four-x", solve for x.

Answers

7x-9=27-4x\n\n7x+4x=27+9\n\n11x=36\ \ \ \ /:11\n\nx=(36)/(11)\n\nx=3(3)/(11)

-x + y = 2
3х – 5у = -4
solve the system of linear equation by substitution

Answers

X=-2 + y
X=5y-4/3
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With Ad = vt + at, solve for Ad given that v; =5.4, a = -9.8, and 1 = 3 d. 74

Answers

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True or false? shapes that have no right angles also have no perpendicular segments?

Answers

It's false. Sometimes shapes might not have perpendicular segments but this is false.
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