Their ages are jan's age = 19 and tritts age be 11 yaers
Algebra is a branch of mathematics that deals with symbols and the arithmetic operations across these symbols. These symbols do not have any fixed values and are called variables. In our real-life problems, we often see certain values that keep on changing. But there is a constant need to represent these changing values.
Given:
Jan's Age is 3 years less than twice Tritts age.
sum of their ages is 30.
let tritts age be x
jan age= 2x -3
Now, sum of their ages = 30
x+ 2x-3 = 30
3x= 33
x=11
hence, jan's age = 19 and tritts age be 11 yaers
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$\bullet$ B. $14.54999$ rounded to the nearest tenth.
$\bullet$ C. $14.44999$ rounded to the nearest tenth.
$\bullet$ D. $14.55001$ rounded to the nearest tenth.
Can someone explain this one?
The average rate of change in the interval is r{a} = 15.
Given is the equation as -
6x −3 = − 5x +7
We have -
6x −3 = − 5x +7
6x + 5x = 7 + 3
11x = 10
x = 10/11
Therefore, thevalue of [x] will be equivalent to 10/11.
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Answer:
The number of ways to choose a set of 9 pencils from a selection of 10 is 10.
Step-by-step explanation:
According to the combination formula, the total number of ways to select r items from total n items is
Total number of pencils = n = 10
Number of selected pencils = r = 9
The number of ways to choose a set of 9 pencils from a selection of 10 is
Therefore the number of ways to choose a set of 9 pencils from a selection of 10 is 10.