b. How high did the arrow go?
c. How long is the arrow in the air?
a) The velocity of the arrow at its peak is zero
b) The maximum height of the arrow is 31.9 m
c) The time of flight is 5.10 s
Explanation:
a)
The motion of the arrow fired straight upward into the air is a uniformly accelerated motion, with constant acceleration (acceleration of gravity) towards the ground.
The initial velocity of the arrow when it is fired is upward: since the acceleration is downward, this means that as the arrow moves upward, its velocity decreases in magnitude.
Eventually, at some point, the velocity of the arrow will become zero, and then it will change direction (downward) and will start increasing in magnitude. The moment when the velocity raches zero corresponds to the peak of the trajectory of the arrow: therefore, at the peak the velocity is zero.
b)
Since the motion of the arrow is a uniformly accelerated motion, we can use the following suvat equation:
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the displacement
For the arrow, we have:
u = 25 m/s
v = 0 (when the arrow reaches the peak)
(negative because downward)
s is the maximum height reached by the arrow
And solving for s,
c)
In order to find the time it takes for the arrow to reach the maximum height, we use the following suvat equation:
where here we have:
v = 0 is the final velocity at the peak
u = 25 m/s
And solving for t,
This is the time the arrow takes to reach the top of the trajectory: therefore, the total time of flight is twice this value,
Learn more about accelerated motion:
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Kilogram
Newton
Electron
Coulomb
Answer:coulomb
Explanation:
The unit of electric charge is coulomb
Answer:
Coulomb.
Explanation:
Answer:
4.8 m
Explanation:
A transverse wave is a wave in which the oscillation of the particles occur in a direction perpendicular to the direction of motion of the wave.
The amplitude of a transverse wave is the maximum displacement of the wave with respect to the equilibrium position.
The crest of a wave is the position of maximum displacement on the positive side, while the trough of a wave is the position of maximum displacement on the negative side.
This means that the amplitude of a wave is equal to the distance between a crest (or a trough) and the equilibrium position.
Therefore, we have:
where:
d is the distance between the top of a crest and the bottom of a trough
A is the amplitude of the wave
Here we have:
A = 2.4 m
So, we find
A.
It remains constant.
B.
It decreases.
C.
It increases, then decreases.
D.
It increases.