At a Garlic Festival Fun Run, 5/12 of the runners are women. If there are 780 runners, how many are women? How many are men?

Answers

Answer 1

Answer: 455, because if you do 5/12=0.416666..., and then you multiply that to 780 you would get 325, and then you do 780-325 to equal 455.

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0.1 is 10 times as much as

What is the GFC of 72 and 36

Answers

The GCF of 72 and 36 is: 36

List out the factors of each number (72 and 36), and find the common factors between the two numbers.

Factors of 36: 1, 2, 3, 4, 6, 9, 12, 18, 36
Factors of 72: 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72

Looking at the factors above, the common ones are 1, 2, 3, 4, 6, 9, 12, 18, and 36. But... considering we are looking for the "greatest" common factor, our highest number out of the listed ones is 36, making it the greatest common factor of 72 and 36.

What is the expanded form of 430,290,100

Answers

So,

When you write a number in expanded form, you separate each non-zero digit and write it according to its place value.

430,290,100

400,000,000
30,000,000

We don't put anything for the millions place because there are none.

200,000
90,000
100

Then we join each of them with a plus sign.

400,000,000 + 30,000,000 + 200,000 + 90,000 + 100

You would break each part down as if it was an addition problem....
400,000,000+30,000,000+200,000+90,000+100

Can anyone please help me with theseEvaluate the following expression
4(×+2)=
3 (a+2)=
2 (×+3)=

Answers

Answer:

4(x+2) = 4*x + 4*2 = 4x+8

3(a+2) = 3*a + 3*2 = 3a + 6

2(x+3) = 2*x + 2*3 = 2x +6

Hope this help you :3

Step-by-step explanation:

Use the distributive property a(b + c) = ab + ac

4(x + 2) = (4)(x) + (4)(2) = 4x + 8

3(a + 2) = (3)(a) + (3)(2) = 3a + 6

2(x + 3) = (2)(x) + (2)(3) = 2x + 6

Any one knows this one plz

Answers

That's the same as 1.024 ÷ 10⁴

Each time we divide by 10 we move the decimal point one place to the left. If we have to we add zeros at the front.

1.024 ÷ 10⁴ = 0.1024 ÷ 10³ = 0.01024 ÷ 10² = 0.001024 ÷ 10 = 0.0001024

Answer: 0.0001024

The answer is 200-/2605

If the cost to store is $50 and the markup is 10% then what is the selling price

Answers

50 dollars times 10%, or .10 is 5. Add 5 to 50. The answer is $55

Answer:

$55

Step-by-step explanation:

Bella is planning to write in a journal. Some pages will have one journal entry on them, and other pages will have two journal entries on them. If Bella wants to make 10 entries, how many different ways can she write them in her journal?

Answers

The correct answer is:

6 ways.

Explanation:

She wants a total of 10 journal entries.

She can write each entry on a separate page, for 10 pages used.
She can write 8 entries on separate pages and 2 entries on 1 page, for 9 pages used.
She can write 6 entries on separate pages and 2 entries each on 2 separate pages, for 8 pages used.
She can write 4 entries on separate pages and 2 entries each on 3 separate pages, for 7 pages used.
She can write 2 entries on separate pages and 2 entries each on 4 separate pages, for 6 pages used.
She can write 2 entries each on 5 separate pages, for 5 pages used.

Answer: 6 ways

Step-by-step explanation:

Given : Bella is planning to write in a journal.

Some pages will have one journal entry on them, and other pages will have two journal entries on them.

Total required entries to make = 10

We can write 10 =10(1)+0

i.e. she can write one entry one journal entry on each page. → Way 1

10=8(1)+2(1)

i.e. she can write one entry one journal entry per page for 8 pages and 2 journal entries on one page .→ Way 2

10=6+4 = 6(1)+2(2)

i.e. she can write one entry one journal entry per page for 6 pages and 2 journal entries on 2 pages . → Way 3

10=4+6 = 4(1)+2(3)

i.e. she can write one entry one journal entry per page for 4 pages and 2 journal entries on 3 pages .→ Way 4

10=2+8 = 2(1)+2(4)

i.e. she can write one entry one journal entry per page for 2 pages and 2 journal entries on 4 pages .→ Way 5

10=0+10= 0+ 2(5)

i.e. she can write 2 journal entries on 5 pages . → Way 6

Hence, the total number of ways she can write them in her journal = 6

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