suize can run 2.5mile per hr faster then jeff. in the time it takes suize to run 6 mile jeff runs 4 mile find the speed of each runner
Answers
6 miles ... x + 2.5 mile per hr (Suize)
4 miles ... x mile per hr (Jeff)
6 * x = 4 * (x + 2.5)
6 * x = 4 * x + 4 * 2.5
2 * x = 4 * 2.5
2 * x = 10
Jeff: x = 5 mile per hr
Suize: x + 2.5 = 5 + 2.5 = 7.5 mile per hr
Suize runs 7.5 mile per hr, and Jeff 5 mile per hr.
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Which statements about the graph of the function f(x) = 2x2 – x – 6 are true? Check all that apply.The domain of the function is . The range of the function is all real numbers. The vertex of the function is . The function has two x-intercepts. The function is increasing over the interval (, ∞).
Picture is included please help
Answers
Answer:
1/5
Step-by-step explanation: First, turn 1/2 so that the denominator is the same as the other fraction (multiply both by 5 to get 5/10). Now subtract to get 2/10. Then, divide both by 2 to get the fraction in the simplest form.
Answer:
0.2
Step-by-step explanation:
because u have to subtract it
B) x+0.5x=3.15 one solution
C) x+0.05=3.15 one solution
D) 0.05x=3.15 no solution
Answers
Answer:
x+0.05x=3.15
Step-by-step explanation:x= the amount he pays for a pack of pen
x+0.05x=3.15 , which has one solution.
1.05x=3.15
x=3.15/1.05=3
he pays for a pack of pens 3
Answer: x+0.05x=3.15 , which has one solution.
Answers
Joel reads 21 books in the span of 7 months
Answer:21
Step-by-step explanation:
The equation would be 3x
X being months he was on the book club so x would be 7
3(7)=21
Answers
2x+ 4 = 14 2x + 4 = -14
x = 5 or x = - 9
2*5 = 10 +4 = 14 Yes
2*-9 = -18 + 4 = - 14 Yes
2x > 10 2x < - 18
X > 5
X < -9
Answers
Answer:
The answer is
Step-by-step explanation:
The distance between two points can be found by using the formula
where
(x1 , y1) and (x2 , y2) are the points
From the question the points are
(3,4) and (4,-6)
The distance between them is
We have the final answer as
Hope this helps you
Answers
A = l * w
200 = 2l + 2w
solve for either l or w
l = 100 - w
plug into the area equation to get one equation with two variables
A = w(100 - w)
A = -w^2 + 100w
take the derivative
A' = -2w + 100
set the derivative equal to zero
0 = -2w + 100
2w = 100
w = 50
This is the width that maximizes the area
with a width of 50, the length must also be 50 to have a perimeter of 200
therefore, they can rope up to 50 * 50 = 2500 ft^2
Final answer:
The maximum area that can be roped off with 200 feet of rope is 2500 square feet by making the roped off area a square.
Explanation:
The question deals with the optimization of area given a fixed perimeter, which involves the principles of geometry and algebra. Since the area needs to be roped off is a rectangle, and you have 200 feet of rope, your rectangle will have dimensions length (L) and width (W) such that 2L + 2W = 200.
To maximize the area of a rectangle given a fixed perimeter, the rectangle should be a square. So, for a maximum area, the length and width should be equal. Thus, each dimension (length and width) would be 200/4 = 50 feet.
Finally, to find the maximum area, we multiply the length by the width: 50 feet * 50 feet = 2500 square feet. So, the maximum area that they can rope off with 200 feet of rope is 2500 square feet.
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