Answer:
The time in which the pendulum does a complete revolution is called the period of the pendulum.
Remember that the period of a pendulum is written as:
T = 2*pi*√(L/g)
where:
L = length of the pendulum
pi = 3.14
g = 9.8 m/s^2
Here we know that L = 14.4m
Then the period of the pendulum will be:
T = 2*3.14*√(14.4m/9.8m/s^2) = 7.61s
So one complete oscillation takes 7.61 seconds.
We know that the pendulum starts moving at 8:00 am
We want to know 12:00 noon, which is four hours after the pendulum starts moving.
So, we want to know how many complete oscillations happen in a timelapse of 4 hours.
Each oscillation takes 7.61 seconds.
The total number of oscillations will be the quotient between the total time (4 hours) and the period.
First we need to write both of these in the same units, we know that 1 hour = 3600 seconds
then:
4 hours = 4*(3600 seconds) = 14,400 s
The total number of oscillations in that time frame is:
N = 14,400s/7.61s = 1,892.25
Rounding to the next whole number, we have:
N = 1,892
The pendulum does 1,892 oscillations between 8:00 am and 12:00 noon.
The question involves the concept of a simple pendulum whose number of swings is largely influenced by its length and the acceleration due to gravity. By determining the period of the pendulum, one can figure out the number of oscillations over a given time period. The pendulum's damping constant is negligible in determining the number of oscillations.
The subject of this question involves understanding the concept of a simple pendulum and how it relates to harmonic motion. It is widely known that the mass of the pendulum does not influence the oscillations but rather the length of the pendulum wire and acceleration due to gravity are paramount.
First, the necessary step toward calculating the number of swings would be to calculate the period of the pendulum's oscillation. This is given by the formula T=2*π*sqrt(L/g), where L is the length of the pendulum (14.4m) and g is the acceleration due to gravity (~9.81m/s²). Substituting these values will give us the period, T, in seconds.
The pendulum starts swinging at 8:00 am and at 12:00 noon, 4 hours or 14400 seconds will have passed. Therefore the number of oscillations will be calculated by dividing the total time by one period of oscillation.
It is crucial to note that the damping in this instance is quite small and would not significantly affect the number of oscillations.
#SPJ2
Answer:
C
Explanation:
I just took the lab
B) Find a(t).
C) At t=0, is the particle slowing down or speeding up? Explain.
D) At what time(s), if any, does the particle change directions? Justify your answer.
Any help would be GREATLY appreciated! Thank you!!!
B. walking
C. swimming
D. all of the above
Answer:
D. All of the above
Explanation:
Newton's third law states that:
"when an object A exerts a force on an object B, object B exerts an equal and opposite force on object A. These forces are called action and reaction"
Let's analyze each situation:
A. when hitting a baseball with a bat --> we have two objects (the baseball and the bat), so we have a pair of forces: the action is the force exerted by the baseball on the bat, while the reaction is the force exerted by the bat on the baseball
B. walking --> in this case, the two objects we should consider are the man walking and the road: the action is the force exerted by the feet of the man on the road, while the reaction is the force exerted by the road on the feet of the man, which allows him walking
C. swimming --> in this case, the two objects we should consider are the man swimming and the water around him: the action is the force exerted by the body of the man on the water, while the reaction is the force exerted by the water on the body of the man, which allows him to swim.
So, all the three choices are correct.
B. Mercury, Jupiter, Saturn, and Mars.
C. Mercury, Venus, Jupiter, and Mars.
D. Mercury, Venus, Earth, and Mars