What is the distance between points (4, −7) and (−5, 9)? Round to the nearest tenth of a unit.

Answers

Answer 1
Answer: they are 18.4 units away from eachother

Answer 2
Answer: Here is the distance formula; hopefully that helps. Note that the whole formula is square rooted! 
d= \sqrt{( x_{2}- x_{1) } }{2} ( y_{2} - y_{1} ){2} [/tex]

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Shelly biked 21 miles in 4 hours. What is Shelly's average speed in miles per hour? At that same rate how many hours will it take Shelly to bike 42 miles?

Answers

So, we need to do the distance she travelled (21 miles) divided by the rate at which she travelled (4 hours). Therefore, because 21 divided by 4 is 5.25, she biked at a speed of 5.25 mph (Miles per hour). So, if she bikes 5.25 miles every hour we can divide 42 by 5.25 to get the time it would take her to travel 42 miles. Now, 42 divided by 5.25 equals 8, so that means for Shelly to bike 42 miles at her average speed of 5.25 mph, it would take her 8 hours.

Answer:

5.25 mph , for 42 mile she would ride around  8 hours

Step-by-step explanation:

you need to divide the 21 miles by the 4 hours to find how many miles Shelly rode for one hour and that will be your answer ( 5.25 mph)

What is 1/3 + 3/2
please help me

Answers

Solution: 1/3 = 2/6
               3/2 = 9/6
       
                2/6 + 9/6 = n

Answer: 11/6 or 1 5/6

Jane and Sue decide to make friendship bracelets for all their classmates. Jane brings 4.5 feet of string, and together they have 10 feet of string. How many feet of string did Sue bring

Answers

5.5 ft

10 - 4.5 = 5.5

A vat has a capacity of 642 fl oz. estimate the capacity in cups

Answers

Solve:- 
1 cup = 8 fl oz

Convert:-

642 ÷ 8 = 80.25

642 fl oz = 80.25 cups
About 80 cups

Is 1/3 more than 2/6

Answers

No they are equal, reduce 2/6 to get 1/3 
They are equal to each other

62% of 150 is what number

Answers

First put the percent into decimal form. This is .62.
Then multiply .62 by 150. This is 93. 93 is 62% of 150.
Put 62/100 = x/150. If you simplify you should be able to get your answer.