What are the divisions within a shell called

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Answer 1
Answer: The divisions within an atom's shell are called subshells. This means that each shell consists of several subshells that are made up of orbitals. Each orbital consists of 1 or 2 electrons. The outermost shell of an atom is what we call the valence electrons, and they are what participate in chemical bonding.

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Which universal force acts on protons and neutrons in an atom's nucleus?

Answers

The strong nuclear force

The strong nuclear force

If you know the components of a vector, what mathematical relationship can be used to find the magnitude of the vector?

Answers

You will always use Pythagoras theorem to find magnitude while given components of vector.
No matter if system that you are observing is 2D or 3D or higher (which is imaginery) pythagoras theorem will be applied.

Formula for determining magnitude is:
M =  √(x^ + y^2 + z^2 + ...)

Number of turms inside square root you take depending on dimension of your system.

A 15 kg box is sliding down an incline of 35 degrees. The incline has a coefficient of friction of 0.25. If the box starts at rest, how fast is it moving after it travels 3 meters?

Answers

The box has 3 forces acting on it:

• its own weight (magnitude w, pointing downward)

• the normal force of the incline on the box (mag. n, pointing upward perpendicular to the incline)

• friction (mag. f, opposing the box's slide down the incline and parallel to the incline)

Decompose each force into components acting parallel or perpendicular to the incline. (Consult the attached free body diagram.) The normal and friction forces are ready to be used, so that just leaves the weight. If we take the direction in which the box is sliding to be the positive parallel direction, then by Newton's second law, we have

• net parallel force:

F = -f + w sin(35°) = m a

• net perpendicular force:

F = n - w cos(35°) = 0

Solve the net perpendicular force equation for the normal force:

n = w cos(35°)

n = (15 kg) (9.8 m/s²) cos(35°)

n ≈ 120 N

Solve for the mag. of friction:

f = µn

f = 0.25 (120 N)

f ≈ 30 N

Solve the net parallel force equation for the acceleration:

-30 N + (15 kg) (9.8 m/s²) sin(35°) = (15 kg) a

a ≈ (54.3157 N) / (15 kg)

a ≈ 3.6 m/s²

Now solve for the block's speed v given that it starts at rest, with v₀ = 0, and slides down the incline a distance of ∆x = 3 m:

v² - v₀² = 2 ax

v² = 2 (3.6 m/s²) (3 m)

v = √(21.7263 m²/s²)

v ≈ 4.7 m/s

Lightning strikes 16,090 meters away from you.How long does it take the sound of thunder to get to you at 20°C temperature?


with solution and formula<3

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Final answer:

It takes approximately 47 seconds for the sound of thunder to reach you at 20°C temperature.

Explanation:

The time it takes for the sound of thunder to reach you can be determined using the formula:

Time = Distance / Speed

Sound travels at a speed of approximately 343 meters per second at 20°C. Therefore, to calculate the time it takes for the sound to reach you, divide the distance by the speed:

Time = 16,090 meters / 343 meters per second

Time = 46.97 seconds

So, it takes approximately 47 seconds for the sound of thunder to reach you at 20°C temperature.

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A baseball of mass 250g, pitched with a speed of 40m/s is caught by the catcher, whose glove moves backward 0.25m while stopping the ball. What was the kinetic energy of the ball before it was caught?

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I don't think we care about the motion of the catcher's glove. 

The mass of the ball is 0.25kg and its speed is 40m/s. 
So its kinetic energy is . . .

     KE = 1/2 (mass) (speed)² =
 
               (0.125 kg) (40m/s)² =

                        200 kg-m²/s² = 200 joules .


The kinetic energy is =.5mv^2 so the amount the glove moved beforehand is irrelevant and typically this is measured in Kgm/s so 250g is .25kg and v^2 is 40x40 so 1600 lastly 1600x.5x.25 is 200kgm/s :)

A blue-light photon has a wavelength of4.80 × 10^−7 meter. What is the energy of the
photon?
(1) 1.86 × 10^22 J (3) 4.14 × 10^−19 J
(2) 1.44 × 10^2 J (4) 3.18 × 10^−26 J

Answers

Energy = hc/λ, where h is planck's constant, c is the speed of light and λ is the wavelength.

Energy = (6.626 x 10^-34*3.00 x 10^8)/(4.80 × 10^−7)= 4.14*10^-19 J, which is 3.

Normally, when solving these equations, don't forget to check the units are correct (eg. wavelength is in meters) and dont forget to include the units in the calculation.






Taking into account the definition of photon, energy of a photon, wavelength, frecuency and propagation speed, the correct answer is the option (3): The energy of a photon with aa wavelength of 4.80×10⁻⁷ meter is 4.14×10⁻¹⁹ J.

What is a photon and energy of a photon

You have to know that electromagnetic radiation carries energy, which can be absorbed or emitted. To explain the processes of emission and absorption, Plank and Einstein proposed that the energy of radiation is composed of indivisible units (quanta). In each elemental process only a quantum of light can be emitted or absorbed. Each of these quanta was called a "photon".

The exchanges of energy between matter and radiation take place not continuously, but by discrete and indivisible quantities or quanta of energy. The quantum of energy is proportional to the frequency of radiation.

The relationship between the amount of energy (E) transported by the photon and its frequency (f) is determined by the following expression, where the energy of a photon is obtained by multiplying Planck's constant h by the frequency f of electromagnetic radiation:

E=h×f

What is wavelength, frecuency and propagation speed

Wavelength is the minimum distance between two successive points on the wave that are in the same state of vibration. It is expressed in units of length (m).

On the other side, frequency is the number of vibrations that occur in a unit of time. Its unit is s⁻¹ or hertz (Hz).

Finally, the propagation speed is the speed with which the wave propagates in the medium, that is, it is the magnitude that measures the speed at which the wave disturbance propagates along its displacement.

The propagation speed relate the wavelength (λ) and the frequency (f) inversely proportional using the following equation:

v = f×λ

All electromagnetic waves propagate in a vacuum at a constant speed of 3×10⁸ m/s, the speed of light.

What is the energy of the photon in this case

In this case, you know:

  • h=  6.63*10⁻³⁴ Js
  • f= v÷λ where v= 3×10⁸ m/s and  λ=4.80×10⁻⁷ m

Replacing in the definition of energy of a photon:

E=h× (v÷λ)

E= 6.63×10⁻³⁴ Js× (3×10⁸ m/s ÷4.80×10⁻⁷ m)

Solving:

E= 4.14×10⁻¹⁹ J

Finally, the correct answer is the option (3): The energy of a photon with aa wavelength of 4.80×10⁻⁷ meter is 4.14×10⁻¹⁹ J.

Learn more about

definition of photon and energy of a photon:

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wavelength, frecuency and propagation speed:

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