Dosha is creating a new dessert that has two layers shaped like cones. The inner cone is frozen ice cream and has a diameter of 12 cm and a height of 6 cm. The outer layer is a thin wafer shell, like an upside-down ice cream cone, with a height of 15 cm and the same diameter as the inner layer. Dosha will inject a cream filling into the space.What is the volume of the cream filling?
Use 3.14 to approximate pi and express your final answer in hundredths.


cm3

nvm.. it was 339.12 !

Answers

Answer 1
Answer: Given:
Inner cone: diameter = 12 cm ; height = 6 cm
Outer layer: diameter = 12 cm ; height = 15 cm

Volume of a cone = π r² h/3

Inner cone: V = 3.14 * (6cm)² * 6cm/3 = 3.14 * 36cm² * 2cm = 226.08 cm³
Outer layer: V = 3.14 * (6cm)² * 15cm/3 = 3.14 * 36cm² * 5cm = 565.20 cm³

Volume of Outer layer :         565.20 cm³
less: Volume of inner layer: 226.08 cm³
Volume of cream filling:        339.12 cm³

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Answers

Answer:

x = - 22, x = 4

Step-by-step explanation:

Given

(x + 9)² = 169 ( take the square root of both sides )

x + 9 = ± √(169) = ± 13 ( subtract 9 from both sides )

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A normal window is constructed by adjoining a semicircle to the top of an ordinary rectangular window, (see figure ) The perimeter of the window is 12 feet. what dimensions will produce a window of maximum area? (Round you answers to two decimal places ) what is the width x= what is the length y.?(Question2) write the function in the form f(×) = ×^3- 6×^2- 15×+9, k = -2.
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Answers

Let's find the perimeter of the window.

The bottom side is x. The left and right sides make 2y.
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x+2y+\frac{1}2\pi x=12

We only want to use one variable to create the area formula, so let's solve for y.

2y=12-x-\frac{1}2\pi x

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Now that we have a value for y in terms of x, we can find the area in terms of x.

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A_r=6x-\frac{1}2x^2-\frac{1}4\pi x^2

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A_(sc)=\frac{1}2\pi \frac{1}4x^2

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If you wanted to factor out \frac{1}8 like you did, this would become

\boxed{A(x)=\frac{1}8(48x=4x^2-\pi x^2)}

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Let's put our equation in the general form of a quadratic.

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Answers

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