2Na + 2H2O 2NaOH + H2
Answer: YES
Explanation: The given chemical equation can be balanced by balancing the stiochiometric number of each and every element.
This rule is in accordance with the Law of Conservation of Masses which states that the masses of the elements in any chemical equation are constant at any instant of time.
Thus the given equation can be written as
Answer : The number of moles of hydrogen gas needed are, 0.253 mole
Explanation : Given,
Moles of water = 0.253 mole
Now we have to calculate the moles of hydrogen gas.
The given balanced chemical reaction is,
From the balanced reaction we conclude that,
As, 2 moles of water obtained from 2 moles of hydrogen gas
So, 0.253 moles of water obtained from of hydrogen gas
Therefore, the number of moles of hydrogen gas needed are, 0.253 mole
Answer: ratio is 10⁻⁵
Explanation:
From Acid-dissociation equilibrium constant, HA is given thus,
HA + H₂O ⇄ H₃O⁺ + A⁻
equilibrium constant, Ka = [H₃O⁺] [A⁻] / [HA]
[H₃O⁺] = Ka [HA] / [A⁻]
from this we have that
pH = -log[H₃O⁺]
and pKa = -logKa
Applying Henderson-Hassel bach equation;
pH = pKa + log [A⁻]/[HA] ...........(1)
A⁻ rep the salt and HA rep the acid
at a given pH of 7, the pKa value of carboxylic acid COOH is 3
∴ from equation (1).
7 = 3 + log(COO⁻/COOH)
log(COO⁻/COOH) = 4
thus (COO⁻/COOH) = 10⁻⁴ ...................(2)
The ratio of alanine COOH to COO- at pH 7 is (COO⁻/COOH) = 10⁻⁴
(ii) Also considering the ratio of alanine NH2 to NH3+ at pH 7 we have;
given Pka value is 8,
therefore pH = pKa + log [salt]/[base]
7 = 8 + log (NH₂/NH₃)
(NH₂/NH₃) = 10⁻¹
thus the ratio of the concentration of the neutral amino acid species to the zwitterionic species at pH 7 is;
10⁻⁴ ˣ 10⁻¹ = 10⁻⁵
cheers i hope this helps