a commercial jet and a private airplane fly from Denver to phoenix. it takes the commercial jet 1.1 hours for the flight, and it takes the private airplane 1.8 hours. the speed of the commercial jet is 210 miles per hour faster than the speed of the private airplane. Find the speed of both airplanes​

Answers

Answer 1
Answer:

Answer:

The speed of thecommercial jet is 540mi/h while the speed of the private airplane is 330mi/h

Step-by-step explanation:

Let's name the commercial jet as cj and private airplane as pa, so we know the following:

It takes the commercial jet 1.1 hours for the flight, so:

t_(cj)=1.1h

It takes the private airplane 1.8 hours for the flight, so:

t_(pa)=1.8h

The speed of the commercial jet is 210 miles per hour faster than the speed of the private airplane:

Let's name the speed of the commercial jet as v_(cj) and the speed of the private airplane as v_(pa), then:

v_(cj)=v_(pa)+210

From physics we know that:

v=(d)/(t) \n \n Where: \n \n v: \ speed \n \n d: \ distance \n \n t: \ time

Since the distance from Denver to phoenix is unique, then:

d_(cj)=d_(pa)=d

Thus, from the equation v_(cj)=v_(pa)+210 and given the relationship v=(d)/(t) we have:

v_(cj)=v_(pa)+210 \n \n (d)/(t_(cj))=(d)/(t_(pa))+210 \n \n \n Plug \ in \ t_(cj)=1.1 \ and \ t_(pa)=1.8 \ then: \n \n (d)/(1.1)=(d)/(1.8)+210 \n \n Isolating \ d: \n \n d((1)/(1.1)-(1)/(1.8))=210 \n \n (35)/(99)d=210 \n \n d=(99* 210)/(35) \n \n d=594miles

Finally, the speeds are:

\bullet \ v_(cj)=(d)/(t_(cj)) \n \n v_(cj)=(594)/(1.1) \therefore \boxed{v_(cj)=540mi/h} \n \n \n \bullet \ v_(pa)=(d)/(t_(pa)) \n \n v_(pa)=(594)/(1.8) \therefore \boxed{v_(pa)=330mi/h}


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