The kinetic energy 22,500 joules
The calculation can be done as follows
mass= 0.5 kg
time= 300 m/s
Kinetic energy= 1/2mv²
= 1/2 × 0.5 × 300²
= 0.5 × 0.5 × 90,000
= 22,500
Hence the Kinetic Energy is 22,500 joules
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KE = 22500 J
KE= 1/2mv^2
1/2*.5*300^2
that's your answer AND formula.
Answer:
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Explanation:
thats what i put got a 100
B) Mean 3 and standard deviation 5
C) Mean 3 and standard deviation 7
D) Mean 17 and standard deviation 1
E) Mean 17 and standard deviation 5
The mean and standard deviation of the distribution of R−S is;
Option B; Mean 3 and standard deviation 5
We are given details of two random variables R and S.
RandomVariableR;
- Mean; μ_R = 10
- Standard deviation; σ_R = 4
RandomVariable S;
- Mean; μ_S = 7
- Standard Deviation; σ_S = 3
We want to carry out R - S for both mean and standard deviation
1) For Mean; R - S would simply be done by subtracting normally as done in arithmetic operations.
Thus; μ_R - μ_S = 10 - 3
μ_R - μ_S = 7
2) For standard deviation;
We know that standard deviation is not independent as it is the square root of variance.
Therefore, if we want to add or subtract standard deviations, it means that the variation will increase.
Thus, the difference in standard deviation is;
σ_R - σ_S = √((σ_R)² + (σ_S)²)
σ_R - σ_S = √((4)² + (3)²)
σ_R - σ_S = √25
σ_R - σ_S = 5
In conclusion, the distribution of R - S gives;
Mean = 3 and Standard deviation = 5
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Answer: B
Mean of 3 and Standard deviation of 5
Explanation:
Performing operations on means of independent variables is similar to performing arithmetic operations on natural numbers.
Subtracting the mean of S from R is 10 - 7 = 3
For the difference in standard deviation. It should be noted that when combining variables, the variation within the distribution. So therefore, adding or subtraction of variables, the variation will increase and will yield same answer.
To obtain the difference in standard deviation, the variances of the random variables has to be added and then the square root will be taken to return back to standard deviation.
SD(R-S)=sqrt(R²+S²)
SD=sqrt(4²+3³)
SD=sqrt(25)
SD=5
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1. What are the examples of your work known as in photographs
A. PORTFOLIO. B. VITAE. C.SYLLABUS. D. LAYER
2. What is the educational path for professional photographers?
A. MASTERS IN FINE ARTS. B. TRAINING WITH A PROFFESIONAL PHOTOGRAPHER. C. A DEGREE IN PHOTOGRAPHY D. THERE IS NO UNIFORM EDUCATIONAL
REQUIREMENTS
3. scientific photographer concentrates on which subject?
A. SOCIAL ISSUES. B. DISEASE. C. CRIME SCENES. D. FASHION
4. A commercial photographer concentrates on which subject?
A. DISEASE. B. CRIME SCENES. C. FASHION. D. SOCIAL ISSUES
5. Forensic photographers photograph which of the following?
A. PRODUCTS. B. FAMILIES. C. CRIME SCENES. D. PETS
6. A photojournalist would be most likely to be employed by which of the following?
A. NEWSPAPER. B. RESTAURANT. C. TRAVEL AGENCY. D. GOVERNMENT
7. Photographers who own studios are responsible for what costs?
A. ADVERTISING. B. EQUIPMENT MAINTENACE. C. INSURANCE. D. ALL THE ABOVE
8. What is the first step in becoming a professional photographer?
A. GOING TO PHOTOGRAPH SCHOOL. B. INTERNING WITH A PHOTOGRAPHER. C. DECIDING TO FOCUS ON A PARTICULAR AREA OF PHOTOGRAPHY. D. HAVING A PASSION AND INTEREST FOR PHOTOGRAPHY
9. Professional photographers spend very little time improving their work or learning
new skills.
A. TRUE. B. FALSE
10. Professional photographers often spend a great deal of time talking to clients and
editing photographs.
A. TRUE. B. FALSE
11. It is very difficult to enter the field of photography as a career.
A.TRUE B. FALSE
12. The need for photographers is decreasing in the United States.
A. TRUE. B. FALSE
13. In preparing for a career in photography, it is important to develop a strong
portfolio.
A. TRUE. B. FALSE.
14. Freelance photographers often have greater flexibility in the hours they work and
the types of photographs that they can take.
A. TRUE. B. FALSE
15. Many photographers work non-traditional hours, such as weekends.
A. TRUE. B. FALSE
IT IS NOT ADVANCED PLACEMENT ITS PHOTOGRAPHY
ITS PHOTOGRAPHY
ITS PHOTOGRAPHY
Answer:B A B C A B B B A A B B
Explanation:
Answer:
Explanation:
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The metaphor exists "Then scrambled eggs exist a mountain on the platter." Analogizing scrambled eggs to a mountain.
A metaphor exists as a figure of speech that, for rhetorical influence, directly guides one thing by mentioning another. It may furnish clarity or recognize hidden similarities between two various ideas.
At their most basic, metaphors exist utilized to create a direct comparison between two separate things, to ascribe a particular quality to the first.
The word metaphor can be outlined from the Greek word metaphor, suggesting transfer. A metaphor exists as a figure of speech utilized to describe or creatively correspond to different things that are not identical but has similarity. Sometimes, a sentence may sound awkward utilizing metaphors, but it exists a unique method of comparing things.
From the given, The metaphor exists "Then scrambled eggs exist a mountain on the platter." Analogizing scrambled eggs to a mountain.
Common metaphor examples are Life exists a highway. Her eyes existed as diamonds. He exists as a shining star. The snow exists as a white blanket. She exists as an early bird.
To learn more about metaphor refer to:
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