Sodium hydroxide (NaOH) was added to pure water (H2O). Which most likely were the pH values of the water before and after the sodium hydroxide was added to it?A. before = 7, after = 9
B. before = 7, after = 4
C. before = 4, after = 7
D. before = 9, after = 7

Answers

Answer 1
Answer: Before 7 after 9. A pH smaller than 7 indicates acidity with 0 being completely acidic. A pH greater than 7 shows alkalinity with 14 being completely alkaline. 7 is neutral. Since NaOH is alkaline, adding it to a neutral substance would increase the pH and it would increase from 7 to 9.
Answer 2
Answer:

Answer:

A before = 7, after = 9

Explanation:


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66. Calculate the displacement and velocity at times of (a) 0.500 s, (b) 1.00 s, (c) 1.50 s, and (d) 2.00 s for a ball thrown straight up with an initial velocity of 15.0 m/s.

Answers

Answer:

a) t=1s

y = 10.1m

v=5.2m/s

b) t=1.5s

y =11.475 m

v=0.3m/s

c) t=2s

y =10.4 m

v=-4.6m/s  (The minus sign (-) indicates that the ball is already going down)

Explanation:

Conceptual analysis

We apply the free fall formula for position (y) and speed (v) at any time (t).

As gravity opposes movement the sign in the equations is negative.:  

y = vi*t - ½ g*t2 Equation 1

v=vit-g*t  Equation 2

y: The vertical distance the ball moves at time t  

vi: Initial speed

g= acceleration due to gravity

v= Speed the ball moves at time t  

Known information

We know the following data:

Vi=15 m / s

g =9.8 (m)/(s^(2) )

t=1s ,1.5s,2s

Development of problem

We replace t in the equations (1) and (2)  

a) t=1s

y = 15*1 - ½ 9.8*1^(2)=15-4.9=10.1m

v=15-9.8*1 =15-9.8 =5.2m/s

b) t=1.5s

y = 15*1.5 - ½ 9.8*1.5^(2)=22.5-11.025=11.475 m

v=15-9.8*1.5 =15-14.7=0.3m/s

c) t=2s

y = 15*2 - ½ 9.8*2^(2)= 30-19.6=10.4 m

v=15-9.8*2 =15-19.6=-4.6m/s  (The minus sign (-) indicates that the ball is already going down)

Air pressure decreases asa. velocity increases.
b. elevation increases.
c. acceleration decreases.
d. gravity increas

Answers

Elevation increases

Answer:

As elevation increases, air pressure decreases, molecules spread out, and air temperature cools.

Explanation:

When you turn on the light switch in a room, you have completed the _____. open circuit series circuit parallel circuit switch circuit

Answers

A.) When you turn on the light switch in a room, you have completed the "Open Circuit"

Hope this helps!
open circuit...by flipping on the switch you close the circuit and allow electrons to flow to the light bulb

Imagine two billiard balls on a pop table. Ball A has a mass of 7 kilograms and ball B has a mass of 2 kilograms. The initial velocity of the ball A is 6 meters per second to the right, and the initial velocity of the ball B is 12 meters per second to the left.1. When the two balls hit each other, what will happen if it is a perfectly inelastic collision?

Answers

i think they wont bounce back......

a person pushing a stroller starts from rest, uniformly accelerating at a rate of 0.500m/s^2. what is the velocity of the stroller after it has traveled 4.75m?

Answers

You're going to use the constant acceleration motion equation for velocity and displacement:
(V)final²=(V)initial²+2a(Δx)

Given:
a=0.500m/s²
Δx=4.75m
(V)intial=0m
(V)final= UNKNOWN

(V)final= 2.179m/s

Hello!

A person pushing a stroller start from rest uniformly accelerating at a rate of 0.500 m/s². What is the velocity of the stroller after it traveled 4.75 m ?

We have the following data:

a (acceleration) = 0.500 m/s²

Vf (final velocity) = ? (in m/s)

Vi (initial velocity) = 0 m/s

Δx (displacement) = 4.75 m

Solving:

Let's apply the Torricelli Equation, to find the velocity of the stroller, let's see:

V_f^2 = V_i^2 + 2*a*\Delta{x}

V_f^2 = 0^2 + 2*0.500*4.75

V_f^2 = 0 + 4.75

V_f^2 = 4.75

V_f = √(4.75)

\boxed{\boxed{V_f \approx 2.18\:m/s}}\:\:\:\:\:\:\bf\blue{\checkmark}\bf\green{\checkmark}\bf\red{\checkmark}

Answer:

The velocity of the stroller is approximately 2.18 m/s

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\bf\red{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}

What is the mass of a child if the force of gravity on the child's body is 100 N?

Answers

Gravity is 9.81m/s^2 on earth F=m×g
100N=(x)kg×9.81m/s^2
x=10.19kg or more than 22lbs