What is fx over gx when fx is -2x^3+x^2+16x-15 and gx is x + 3
Answers
The next step is to factor the numerator by grouping in the hopes that something will cancel!
Unfortunately, because we can't factor anything out of the second grouped pair, that means there's no simplifying possible! So...
Hope this helps!
Related Questions
Algebra one help please?
14.4% of 72.5 is what
What is the equivalent ratio of 6:3
Solve.: -2 1/3 -(-5) A:-7 1/3 B: 2 2/3 C: 3 2/3 D: 3 1/3
Answers
4x/50 = 2/x take 4x and multiply it by the denominator in the other fraction it = 4x^2 do the same for the 2 &50 you get 100 now you have 4x^2=100 take the 4 divide it on both sides so 4/4=0 and 4/100=25 now you have
x^2=25 find the square root of 25= (5) so X=5
Answers
Answer:
Step-by-step explanation:
: A swimming pool holds 600,000 liters of water. ... When the pool is completely full, the first pipe alone can empty it in 200 minutes, and the ... When both pipes are draining together, how long does it take them to empty the pool? ... The second pipe empties the pool at 600,000/120 =5000 litres per minute.
Answers
Answer:
280
Step-by-step explanation:
Area=bh
18,069,333.333=(193,600)h
multiply both sides by 1/3: 54208000=193,600h
divide both sides by the 193600: h=280
Answers
first is 30
imagine it
ball droppes 30 feet
bounces up 80% of that
then it has to bounce down again
then up
down
therfor, we summ up from 30 to 6thbounce, times 2 and minus 30 since the first bounce didn't start from ground (will include diagram)
so therefor
2(sum)-30 is the answer
the sum of a geometric sequence is
where Sn is the sum to the nth bounce
a1=first term
r=common ratio
n=which term
Sn=S6 (6th bonce)
a1=30
r=80% or 0.8
sub
we then double then minus 30
2*110.678=221.357
minus 30
221.357-30=191.357 feet
you should use
dropped from x feet and max height is m percent of previous heigh, find total distance after n bounces (convert m% to decimal)
answer=
anyway, distance is 191.357 feet
a.v=2/3bh
b. v=1/4bh
c.v=2bh
d.v=1/6bh
Answers
Answer: D) V= 1/6 bh
Step-by-step explanation:
Since according to the given question, A pyramid is placed inside a prism.
And, The pyramid has the same base area, b, as the prism but half the height, h, of the prism.
Therefore, base area of the pyramid = b
Height of the pyramid = h/2
Since, The volume of the pyramid,
V = 1/3 × base ares × height
V= 1/3 × b × h/2
V= 1/6 bh
Thus the required volume = 1/6 bh cube unit.
Therefore Option D is correct.
Answer:
V = 1/6 BH
Im also taking this class on edmentum
Step-by-step explanation:
the volume of a pyramid is 1/3 BH , since the pyramid is only half the height of the prism you'll have to multiply 1/3 x 2 = 1/6
Answers
A = l * w
200 = 2l + 2w
solve for either l or w
l = 100 - w
plug into the area equation to get one equation with two variables
A = w(100 - w)
A = -w^2 + 100w
take the derivative
A' = -2w + 100
set the derivative equal to zero
0 = -2w + 100
2w = 100
w = 50
This is the width that maximizes the area
with a width of 50, the length must also be 50 to have a perimeter of 200
therefore, they can rope up to 50 * 50 = 2500 ft^2
Final answer:
The maximum area that can be roped off with 200 feet of rope is 2500 square feet by making the roped off area a square.
Explanation:
The question deals with the optimization of area given a fixed perimeter, which involves the principles of geometry and algebra. Since the area needs to be roped off is a rectangle, and you have 200 feet of rope, your rectangle will have dimensions length (L) and width (W) such that 2L + 2W = 200.
To maximize the area of a rectangle given a fixed perimeter, the rectangle should be a square. So, for a maximum area, the length and width should be equal. Thus, each dimension (length and width) would be 200/4 = 50 feet.
Finally, to find the maximum area, we multiply the length by the width: 50 feet * 50 feet = 2500 square feet. So, the maximum area that they can rope off with 200 feet of rope is 2500 square feet.
Learn more about Optimization of Area here:
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