Each parking lot can hold 185 cars.
Math operations include division as one of its types. This technique involves splitting the phrases or numbers into the same amount of components.
Let's denote the number of cars each parking lot can hold as x.
Since there are six identicalparking lots, the total number of cars they can hold is 6x.
According to the problem, the total number of cars that can be parked in these six lots is 1110.
So we can write:
6x = 1110
This equation relates the number of cars each parkinglot can hold (x) to the total number of cars that can be parked in all six lots (1110).
To solve for x, we can divide both sides of the equation by 6:
x = 185
Therefore, the required number is 185 cars.
To learn more about the division;
#SPJ3
a function is a rule that assigns each value of the variable to exactly one value of the dependent variable
Answer:
the answer is 32.50
Step-by-step explanation:
I added the two totals and then multiplyed them by 5
Answer:
6.55
Step-by-step explanation:
Answer:
3√2
Step-by-step explanation:
Pythagoras says s²+s²=6²
so
2s² = 36
s = √18 = √9·2 = √3²·2 = 3√2
Answer:
C
Step-by-step explanation:
The diagonal splits the square into 2 right triangles with hypotenuse 6
Using Pythagoras' identity in one of the right triangles.
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
s² + s² = 6²
2s² = 36 ( divide both sides by 2 )
s² = 18 ( take the square root of both sides )
s = = = × = 3 → C
Answer:3/8
Step-by-step explanation: