a 4/3
b 7/3
c 3/2
d 11/2
digits from 0 to 9. Digits cannot be
repeated. Find the probability that
randomly generated card has the
exact number 94213.
Answer:
Step-by-step explanation:
Given
ID Card of 5 digits
Possibly Digits = {0,1...,9}
Required
Probability that a card has exact number 94213
First, we have o determine the total possible number of ID card numbers
Let the card number be represented by ABCDE
Given that repetition of digits is not allowed;
A can be any of 10 digits
B can any of the remaining 9 digits
C can be any of the remaining 8 digits
D can be any of the remaining 7 digits
E can be any of the remaining 6 digits
Total number of cards = 10 * 9 *8 * 7 * 6
Total = 30240
Provided that the card number is generated at random; each card number has the same probability of
Hence, the probability of having 94213 is
Answer: 2/3
Step-by-step explanation:
6 whole
Subtract the eaten fraction:
6 - denominator
2 - numerator
Thus,
6/6 - 2/6 = 4/6
Simplify: 4/6 = 2/3
Answer:
i think its 1/4
Step-by-step explanation:
Idk if I followed the PEMDAS right
yes you did a very good job