What is y- intercept?

Answers

Answer 1
Answer: In the equation of a straight line, the y- intercept is the point where the line crosses the y axis.
Answer 2
Answer: the vertical line crossing with the x- intercept in graphs.

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In right triangle ABC, angle B is a right angle. sin A = 2/3 and the length of BC is 6 meters. What is the length, in meters, of AC?

Answers

The length of AC is 9 meters

Step-by-step explanation:

The given scenario forms a right-angled triangle where Perpendicular = 6m (Picture Attached)

The trigonometric ratios can be used to find the required length.

When an angle is under consideration the side opposite to angle is perpendicular.

So,

sin\ A = (P)/(H)

(2)/(3) = (BC)/(AC)\n(2)/(3) = (6)/(AC)\nAC = 6 * (3)/(2)\nAC = 3*3\nAC = 9m

Hence,

The length of AC is 9 meters

Keywords: Triangle, right angles

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The ratio of X and 2 is not greater than 14

Answers

Well if it's not greater than, then it has to be less than or equal to...

x/2 <= 14
2 × x/2 <= 14 × 2
x <= 28

a pizza place charges $15 for a pepperoni pizza and $12 for a cheese pizza. the goal is to sell $540 in pizza for the day. The situation can be represented by the equation 15x+12y=540, x=pepperoni pizzas and y= cheese pizzas. If the pizza place runs out of pepperoni, how many cheese pizzas must be sold to reach the daily goal?

Answers

Answer:

$45

Step-by-step explanation:

540 divided by 12 = y

Question on circumference photo attached

Answers

A
as the radius is always half of the circumference to next time think first, what is the half of the circumference 

In which quadrant is the number 6 – 8i located on the complex plane?I
II
III
IV

Answers

The number 6 - 8i is located in the thirdquadrant of the complex plane.

Option C is the correct answer.

What are quadrants?

The term "quadrants" usually refers to the four regions of the Cartesian plane, which is a two-dimensional coordinate system.

The plane is divided into four regions called quadrants, labeled I, II, III, and IV, which are numbered counterclockwise starting from the upper right quadrant (I).

Quadrant I: The point has positive x and positive y coordinates.

Quadrant II: The point has negative x and positive y coordinates.

Quadrant III: The point has negative x and negative y coordinates.

Quadrant IV: The point has positive x and negative y coordinates.

We have,

To determine the quadrant where the complexnumber 6 - 8i is located, we need to consider the signs of the real and imaginary parts of the number.

The realpart of the number is 6, which is positive, indicating that the number lies to the right of the origin.

The imaginarypart of the number is -8i, which is negative, indicating that the number lies below the origin.

Therefore,

The number 6 - 8i is located in the thirdquadrant of the complex plane.

Learn more about quadrants here:

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Answer:

IV

Step-by-step explanation:

The 6 is to the right of the  x axis ( positive x) and the -8i is  below the x axis to the right.

How do you turn 12/15 and 68/80 into a decimal and into a percent

Answers

(12)/(15)\n\ndivide\ a\ numerator\ and\ a\ denominator\ by\ 3\n\n12:3=4;\ 15:3=5\n\ntherefore\ (12)/(15)=(4)/(5)\n\nmultiply\ a\ numerator\ and\ a\ denominator\ by\ 2\n\n4\cdot\ 2=8;\ 5\cdot2=10\n\ntherefore\ (12)/(15)=(4)/(5)=(8)/(10)=\boxed{0.8}\Rightarrow0.8\cdot100\%=\boxed{80\%}



(68)/(80)\n\ndivide\ a\ numerator\ and\ a\ denominator\ by\ 4\n\n68:4=17;\ 80:4=20\n\ntherefore\ (68)/(80)=(17)/(20)\n\nmultiply\ a\ numerator\ and\ a\ denominator\ by\ 5\n\n17\cdot\ 5=85;\ 20\cdot5=100\n\ntherefore\ (68)/(80)=(17)/(20)=(85)/(100)=\boxed{0.85}\Rightarrow0.85\cdot100\%=\boxed{85\%}
\frac{\big{12}}{\big{15}}= \frac{\big{3\cdot4}}{\big{3\cdot5}}= \frac{\big{4}}{\big{5}}= \frac{\big{4\cdot2}}{\big{5\cdot2}}= \frac{\big{8}}{\big{10}}=0.8 \n\n1\%\ \ \rightarrow\ \ 0.01\ \ \ \ \ \ \Rightarrow\ \ \ \ \ 10\%\ \ \rightarrow\ \ 0.01\cdot10=0.1\n\n0.8=8\cdot0.1 \ \rightarrow\ \ 8\cdot10\%=80\%\n\n--------------------\n\n

\frac{\big{68}}{\big{80}}=\frac{\big{4\cdot17}}{\big{4\cdot20}}=\frac{\big{17}}{\big{20}}=\frac{\big{17\cdot5}}{\big{20\cdot5}}=\frac{\big{85}}{\big{100}}=0.85\n\n0.85=0.8+0.05=8\cdot0.1+5\cdot0.01\n\n0.85\ \ \rightarrow\ \ 8\cdot10\%+5\cdot5\%=80\%+5\%=85\%