ground 54 m horizontally from the point of
release.
What is the speed of the ball just before it
strikes the ground?
Answer in units of m/s.
Answer:
v = d / t = 54 / 5.34 = 10.11 m/s (rounded to two decimal places)
Explanation:
6 ... A
9 ... A
10 ... ok
12 ... A
23 ... ok
24 ... A
9
5
8
please help