The probability that an adult possesses a credit card is .70. A researcher selects two adults at random. By assuming the independence, the probability that the first adult possesses a credit card and the second adult does not possess a credit card is:

Answers

Answer 1
Answer:

Answer: 0.21

Step-by-step explanation:

We know that if two events A and B are independent , then the probability of A and B is given by :-

\text{P and B}=P(A)* P(B)

Given: The probability that an adult possesses a credit card P(A)= 0 .70

The probability that an adult  does not possess a credit cardP(B)= 1-P(A)=0 .30

By assuming the independence, the probability that the first adult possesses a credit card and the second adult does not possess a credit card is given by :-

0.70*0.30=0.21

Hence, the probability that the first adult possesses a credit card and the second adult does not possess a credit card is 0.21.


Related Questions

Geometry, 1 question
Hello, please I bed urgent help with this math problem please
There are 45 new houses being built in a neighborhood. Last month, 1/3 of them were sold. This month, 1/5 of the remaining houses were sold. How many houses are left be sold?
The best fit line is given by the equation y=0.5x+0.4, where y represents the distance in miles, and x represents the time for the trip in minutes.Use the best fit line to estimate the distance for a trip that takes 20 minutes.Enter your response in the box. Give the answer to the tenths place.miles
Multiply the polynomials 3(x+7) (show work pls)

Please help asap!!!Factor 5y + 5w.

A) 5y(5 + w)
B) (5y + 5)w
C) y(5 + 5w)
D) (y + w)5

Answers

5y + 5w

factor out a 5

5(y+w)

Choice D

the 5 can go on either end of (y+w)

D I think because you have to multiply 5 with both y and w.

Sanderson Manufacturing produces ornate, decorative wood frame doors and windows. Each item produced goes through three manufacturing processes: cutting, sanding, and finishing. Each door produced requires 1 hour in cutting, 30 minutes in sanding, and 30 minutes in finishing. Each window requires 30 minutes in cutting, 45 minutes in sanding, and 1 hour in finishing. In the coming week Sanderson has 40 hours of cutting capacity available, 40 hours of sanding capacity, and 60 hours of finishing capacity. Assume all doors produced can be sold for a profit of $500 and all windows can be sold for a profit of $400.Required:
a. Formulate an LP model for this problem.
b. Sketch the feasible region.
c. What is the optimal solution?

Answers

Answer:

Let X1 be the number of decorative wood frame doors and X2 be the number of windows.  

The profit earned from selling each door is $500 and the profit earned from selling of each window is $400.  

The Sanderson Manufacturer wants to maximize their profit. So for this model, the objective function is

Max: 500X1 + 400X2

Now the total time available for cutting of door and window are 2400 minutes.  

so the time taken in cutting should be less than or equal to 2400.  

60X1 + 30X2 ≤ 2400  

The total available time for sanding of door and window are 2400 minutes. Therefore, the time taken in sanding will be less than or equal to 2400.   30X1 + 45X2 ≤ 2400  

The total time available for finishing of door and window is 3600 hours. Therefore, the time taken in finishing will be less than or equal to 3600. 30X1 + 60X2 ≤ 3600  

As the number of decorative wood frame door and the number of windows cannot be negative.  

Therefore, X1, X2 ≥ 0

so the questions

a)

The LP mode for this model is;

Max: 500X1 + 400X2  

Subject to:  

60X1 + 30X2 ≤ 2400  

]30X1 +45X2 ≤ 2400  

30X1 + 60X2 ≤ 3600  

X1, X2 ≥ 0  

b) Plot the graph of the LP  

Max: 500X1+ 400X2  

Subject to:  

60X1 + 30X2 ≤ 2400  

30X1 + 45X2 ≤ 2400  

30X1 + 60X2 ≤ 3600

X1,X2  

≥ 0

In the uploaded image of the graph, the shaded region in the graph is the feasible region.  

c) Consider the following corner point's (0,0), (0, 53.33), (20, 40) and (40, 0) of the feasible region from the graph  

At point (0, 0), the objective function,  

500X1 + 400X2 = 500 × 0 + 400 × 0  

= 0

At point (0, 53.33), the value of objective function,

500X1 + 400X2 = 500 × 0 + 400 × 53.33 = 21332  

At point (40, 0), the value of objective function,  

500X1 + 400X2 = 500 × 40 + 400 × 0 = 20000  

At point (20, 40), the value of objective function

500X1 + 400X2 = 500 × 20 + 400 × 40 = 26000  

The maximum value of the objective function is  

26000 at corner point ( 20, 40 )

Hence, the optimal solution of this problem is  

X1 = 20, X2 = 40 and the objective is 26000

Let yequals[Start 3 By 1 Matrix 1st Row 1st Column 3 2nd Row 1st Column negative 7 3rd Row 1st Column 3 EndMatrix ]​, Bold u 1equals[Start 3 By 1 Matrix 1st Row 1st Column negative 3 2nd Row 1st Column negative 5 3rd Row 1st Column 1 EndMatrix ]​, Bold u 2equals[Start 3 By 1 Matrix 1st Row 1st Column negative 3 2nd Row 1st Column 3 3rd Row 1st Column 6 EndMatrix ]. Find the distance from y to the plane in set of real numbers R cubed spanned by Bold u 1 and Bold u 2.

Answers

Answer:

Answer to Let Bold Upper A equals Start 3 By 3 Matrix 1st Row 1st Column 1 2nd ... 1st Column 4 2nd Column 7 3rd Column 0 3rd Row 1st Column negative 4 ...

Step-by-step explanation:

What is the value of a + 4b / a + b if a = -4, b = 3

Answers

Answer:- 8

Step-by-step explanation:

-4 + 4(3)/ -4+3

-4 +12 / -1

8/-1

A paddle boat rents for $10 plus $8 per hour. How much does it cost to rent a paddle boat for h hours? Write an expression and show your work.

Answers

10 + 8h

10 would be the initial cost and would be unchangeable, leaving it as a constant. The $8 on the other hand increases based on the number of hours, making it the constant with the variable next to it.

Hope this helps! 

Please answer this correctly

Answers

Answer:

6 books

Step-by-step explanation:

22, 23, 25, 25, 26, 28

6 books contained at least 22 characters but less than 29.