Answer:
= 51.57 °C
Explanation:
The combined gas equation shows that P₁V₁/T₁=P₂V₂/T₂ where P represents pressure, V represents volume and T absolute temperature
From the information provided in the question,
Since we are finding the initial or original temperature, we can make T₁ the subject of the formula.
T₁=P₁V₁T₂/P₂V₂
P₁=2.0 ATM
P₂= 1.0 ATM
V₁=2.0 L
V₂= 3.5 L
T₁=?
T₂= (11+273) K=284 K
Using these values in the formula:
T₁= (2.0 ATM × 2.0 L× 284 K)/(1.0 ATM × 3.5 L)
=324.57 K
324.57-273= 51.57 °C
The answer is: the atom with more valence electrons are in the middle of a molecule and it form more bonds.
For example, molecule hydrogen cyanide (HCN).
Lewis structure for hydrogen cyanide is H:C:::N:
Hydrogen has valence one (I), it means it has one single bond and electron configuration like closest noble gas helium.
Carbon has valence four (IV), it has four bonds (one with hydrogen and three with nitrogen) and full octet.
Nitron has valence three (III), it has full octet and electron configuration like noble gas neon (Ne).
Hydrogen cyanide has linear shape (the bond angles of 180 degrees).
Answer: 1.
Explanation: The number 1 should never be written in a subscript because the chemical symbol is already there.
Answer:
1
Explanation:
The subscript of 1 is never written in a chemical formula.
Answer:
Most astronomical objects, such as galaxies, stars, and planets
Explanation:
The number of electrons that can be held in the second orbital (closest to the nucleus) is 8 electrons
The arrangementof electrons in various energy levels or orbital follows a well defined order. This can be determined by using the following formula:
Number of electrons = 2n²
Where
Now, we shall obtain the number of electrons in the second orbital. Details below:
Number of electrons = 2n²
= 2 × 2²
= 2 × 4
= 8 electrons
Thus, the number of electrons in the second orbital is 8 electrons
Learn more about number electrons in energy levels:
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