MATHEMATICS MIDDLE SCHOOL

During practice, the Northwood football team drinkswater from a cylindrical cooler that has a radius of 6
inches and a height of 20 inches. Players use conical
paper cups, as shown below.
If the water cooler is filled completely, can each of the
38 players have two full paper cups of water during
practice? Explain
4.4 in.
O No, because there is enough water in the cooler for
about 3 cups total.
No, because there is enough water in the cooler for
about 59 cups total
5.5 in.
Yes, because there is enough water in the cooler
for about 81 cups total.
Yes, because there is enough water in the cooler
for about 2,261 cups total.

Answers

Answer 1

Answer:

The radius and height of the cooler of 6 and 20 inches respectively, can

contain approximately only 81 cups, the correct option is therefore;

Yes, because there is enough water in the cooler for about 81 cups total

How can the correct option be found?

The dimensions of the cooler are;

Radius = 6 inches

Height = 20 inches

The possible dimensions of a cup are;

Diameter = 4.4 inches

Height = 5.5 inches

Required:

If each of the 38 players have 2 paper cups filled with water.

Solution;

The volume of the cooler, V₁, is found as follows;

V₁ = π × 6² × 20 = 720·π

The volume of the cooler, V₁ = 720·π in.³

The volume of the paper cup, V₂, is; $V_2 = (1)/(3) * \pi * \left((4.4)/(2) \right)^2 * 5.5 = 8(131)/(150) \cdot \pi$

The volume of the paper cup, V₂ = $8(131)/(150) \cdot \pi$ in.³

The number of cups, n, in the cooler of water is therefore;

$n = (720 \cdot \pi)/(8 (131)/(150) \cdot \pi ) \approx \mathbf{ 81.14}$

The number of cups of water in the cooler ≈ 81 cups

The number of cups required for each of the 38 player to have two full cups is, Cups = 38 × 2 = 76 cups

Given that the water available, (approximately 81 cups) is more than the

number of cups required (76 cups), the correct option is option;

Yes, because there is enough water in the cooler for about 81 cups total

Learn more aboutthe volume of a cone here:

brainly.com/question/4308629

Answer 2

Answer:

Answer:

The third option (C) Yes, because there is enough water in the cooler for about 81 cups total.Step-by-step explanation:

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WILL NAME BRAINLIEST!The probability of drawing two red balls from a jar at random without replacement is 3/10. The probabilty of drawing a red ball first is 9/16.

What is the probability of drawing a second Redball, given that the first ball drawn was red?

A. 69/80

B. 8/15

C. 21/80

D. 27/160

Answers

Answer:

B. $p = (8)/(15)$

Step-by-step explanation:

The probability of selecting a red and then a red without replacement is as follows:

$(9x)/(16) * (9x)/(16) -1$

This equals the given probability of $(3)/(10)$

More simply, we have the equaiton:

$(9)/(16) * P = (3)/(10)$

So, $p = (8)/(15)$

Answer: 8/15

Step-by-step explanation:

Test

A divers final score 77.7 what is the degree of difficulty of the dive

Answers

the answer is 3.5
I did this in class today! haha

The probability of randomly selecting a name starting with the letter T from a bowl of 24 names is 12/24 . Which of the following describes the likelihood of selecting a name starting with the letter T?unlikely

likely

neither unlikely nor likely

Answers

Its neither unlikely nor likely.

12/24 is 0.5. and 0.5 is 50% so its an equal chance making it unlikely nor likely.

The answer is neither likely nor unlikely. This is because it's a 50% chance of grabbing or not grabbing T. If it was 13/24 chance of grabbing T, it'd be likely. If it was 11/24 it'd be unlikely. I hope this helped.

A sphere and the base of a cone have a radius of 3 inches. The volume of the sphere equals the volume of the cone. what is the height of the cone, in inches?

Answers

So the volume of a sphere is $V= (4)/(3) \pi r^3$ , and the volume of a cone is $V= \pi r^2 (h)/(3)$ (h=height, r=radius). Knowing only the radius, we can solve for the volume of the sphere. (Also I'm going to be leaving answers in pi form.)

$V= (4)/(3) \pi 3^3$
Solve the exponents to get $V= (4)/(3) \pi 9$
Multiply 4/3 and 9 to get $V=13.5 \pi$

Now that we know the volume of the sphere, we can solve for the height of the cone since the volumes for both are the same.

$13.5 \pi = \pi 3^2 (h)/(3)$

Solve the exponents to get $13.5 \pi =9 \pi (h)/(3)$

Divide $9 \pi$ on each side to get $1.5= (h)/(3)$

Multiply 3 on each side, and your answer should be $4.5=h$

Joseph wants to estimate 1 3/7 * 5 4/3 To estimate, he simplifies the expression 1 1/2 * 6

Is Joseph’s estimate a close estimate, an underestimate, or an overestimate?

Answers

$1 (3)/(7) * 5 (4)/(3) = (10)/(7) * (19)/(3) = (190)/(21) \approx 9,0476..$
When he simplified the expression:
$1 (1)/(2) *6= (3)/(2) * (6)/(1) = (18)/(2) = 9$
$9,047 \approx 9,05 \approx 9$
I think Joseph's estimate a close estimate.

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