The diameter of a circle is 25cm and a chord of the same circle is 16cm. To the nearest tenth, what is the distance from the chord to the center of the circle

Answers

Answer 1
Answer:

Answer:

  • 9.6 cm

Step-by-step explanation:

The segment from the center to the chord forms a right triangle with one leg as half the chord and hypotenuse as the radius.

Use Pythagorean to find the length of the missing leg d

  • d^2=(25/2)^2-(16/2)^2
  • d^2=(12.5)^2-(8)^2
  • d^2=92.25
  • d=√(92.25) =9.6 cm (rounded)


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What is 95% of 120 games?

Han has 130$ if she saved 25$ per week in how many weeks will she have 600$

Answers

In 19 weeks this would mean she would have 5 dollars over the amount needed but there can't be half of a week.
She would have 5 dollars over the amount

OMG PLS HELP WITH THIS IM PANICKING OMG I GOT A F IN MATH MY MOM JUST YELLED AT ME IM CRYING PLS HELP WITH THS- PLSS TELL ME WHAT TO DRAW

Answers

I hope this helped you

Solve each system by the addition method.-4x+7y =9
2y=-5x-22
Put the answer in (x,y) form

Answers

-4x + 7y = 9  ⇒ -4x + 7y = 9  ⇒     8x - 14y = -18
2y = -5x - 22 ⇒ -5x - 2y = 22 ⇒ -35x - 14y = 154
                                                               43x = -172
                                                                43       43
                                                                   x = -4
                                                        -4x + 7y = 9
                                                     -4(-4) + 7y = 9
                                                          16 + 7y = 9
                                                        - 16        - 16
                                                                  7y = -7
                                                                   7      7
                                                                    y = -1
                                                              (x, y) = (-4, -1)

(64/9)^(-2/3) Simplify the expression

Answers

cubert64^2 = cubert 4096 then this equals 16
cubert9^2 = cubert81 then this equals 3 cubert3
therefore, ( 16 / 3cubert3)^ -1 so this would shift it to be 3cubert3 / 16

Correct Answer:

0.27042

Solve the system of equations. 3x = ­-31 + 2y
5x + 6y = 23

a. x = ­-5, y = 8
b. x = ­- 29, y = ­- 28
c.no solution
d.infinite solutions

Answers

Answer:

a. x = -5, y = 8

Step-by-step explanation:

\left\{\begin{array}{ccc}3x=-31+2y&\text{subtract}\ 2y\ \text{from both sides}\n5x+6y=23\end{array}\right\n\n\left\{\begin{array}{ccc}3x-2y=-31&\text{multiply both sides by 3}\n5x+6y=23\end{array}\right\n\n\underline{+\left\{\begin{array}{ccc}9x-6y=-93\n5x+6y=23\end{array}\right}\qquad\text{add both sides of the equations}\n.\qquad14x=-70\qquad\text{divide both sides by 14}\n.\qquad x=-5\n\n\text{Put it to the second equation:}\n\n5(-5)+6y=23\n-25+6y=23\qquad\text{add 25 to both sides}\n6y=48\qquad\text{divide both sides by 6}\ny=8

Triangle PQR has vertices P(0, 0), Q(3, 4), and R(3, 0). If triangle PQR is rotated 180° about the origin, what is the length of side P'Q'?

Answers

Answer:

The length of P'Q' is 4 units

The length of P'R' is 3 units

Step-by-step explanation:

If you rotate the figure 180° then the vertex would be R, and from P to Q is 3 units left and 4 units down

Final answer:

To find the length of side P'Q' after rotating triangle PQR 180° about the origin, we need to find the distance between the points P'(0,0) and Q'. When you rotate a point (x, y) 180° about the origin, the new coordinates are (-x, -y). Using the distance formula, we can find the length of side P'Q': d = sqrt((-3-0)^2 + (-4-0)^2) = sqrt(9 + 16) = sqrt(25) = 5. Therefore, the length of side P'Q' is 5 units.

Explanation:

To find the length of side P'Q' after rotating triangle PQR 180° about the origin, we need to find the distance between the points P'(0,0) and Q'.

When you rotate a point (x, y) 180° about the origin, the new coordinates are (-x, -y).

So, the coordinates of point Q' would be (3, 4) rotated 180°, which is (-3, -4).

Using the distance formula, we can find the length of side P'Q':

d = sqrt((-3-0)^2 + (-4-0)^2) = sqrt(9 + 16) = sqrt(25) = 5.

Therefore, the length of side P'Q' is 5 units.

Learn more about rotating triangles here:

brainly.com/question/16631420

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