2x^2+5x-9=0
The quadratic equation 2x^2+5x-9 = 0 has two solutions or zeros, which may be real or complex. They can be found using the quadratic formula: x = [-5 + sqrt(97)]/4 and x = [-5 - sqrt(97)]/4.
The equation given is 2x^2+5x-9=0, which is a quadratic equation. The solutions or zeros of a quadratic equation can be found using the quadratic formula: x = [-b ± sqrt(b^2 - 4ac)]/2a. Here, a=2, b=5, and c=-9.
Let's substitute these values into the formula:
x = [-(5) ± sqrt((5)^2 - 4*2*(-9))]/2*2
x = [-5 ± sqrt(25 + 72)]/4
x = [-5 ± sqrt(97)]/4
Therefore, this equation has "two solutions" or zeros, which are x = [-5 + sqrt(97)]/4 and x = [-5 - sqrt(97)]/4.
#SPJ2
Answer:Fact #1
Step-by-step explanation: because fact #1 is turly correct while fact #2 and #3 is false
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Thank you in advance!
Answer:
Step-by-step explanation:
6 3/4 = 27/4
7600 * 27/4 = 205200/4
51300