A.
Arthropods
B.
Eubacteria
C.
Protista
D.
Animalia
4PCl5(g) → P4(s) + 10Cl 2(g) ΔH = 3438 kJ
The value of ΔH will be 249.75 KJ.
To obtain the reaction :
PCl5(g) → PCl3(g) + Cl2(g)
We have to add the given reactions and then divide it by 4.
(i) adding the reactions
P4(s) + 6Cl2(g) → 4PCl3(g) ΔH = -2439 kJ
4PCl5(g) → P4(s) + 10Cl 2(g) ΔH = 3438 kJ
we get:
4PCl5(g) → 4PCl3(g) + 4Cl2(g), ΔH = 3438 - 2439
(ii) dviding by 4
PCl5(g) → PCl3(g) + Cl2(g) , ΔH = (3438 - 2439)/4
ΔH = 249.75 kJ is the required enthapy.
Learn more about enthalpy:
Answer:
The value of for the desired reaction will be 249.75 KJ.
Explanation:
The desired reaction is shown below
The desired reaction can be obtained by adding the given reactions and then dividing both sides by 4.
Net Enthalpy change for the desired reaction
The diagram which shows electrons violating the Pauli exclusion principle is: C. a box containing an up and a down arrow and 2 other up arrows.
The Pauli exclusion principle can be defined as a principle which states that no two electrons (fermions) in a single atom can have the same values for all four (4) of their electronic quantum numbers.
Furthermore, this principle states that the orbital of an atom can only contain a maximum of two electrons, and they must have opposing spin orientations.
In conclusion, the diagram which shows electrons violating the Pauli exclusion principle is a box containing an up and a down arrow and 2 other boxes with 2 up arrows,that are having the same spin orientations as shown.
Read more on Pauli exclusion principle here: brainly.com/question/10386902
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Answer:
C
Explanation: