PLZ HELP ASAP The sides of a quadrilateral are 3, 4, 5, and 6.
Find the length of the shortest side of a similar quadrilateral whose area is 9 times as great.
I've done everything possible and still keep getting wrong answer... plz help

Answers

Answer 1

Answer: When a shape's area is 9 times as great, the one dimension difference is √9=3 times as great. Therefore the length of all sides are 3 times of the corresponding sides of the original shape. The shortest side in the original shape is 3, the larger one is 3 times of that, which is 9. General rule, if a similar shape is x times ratio in terms of sides, the area will be x^2 times the original. Hope it helps.

Answer 2

Answer:

Answer:

Step-by-step explanation:

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Answers

Answer:

C. snowball sampling

Step-by-step explanation:

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What fractions would be equivalent to 4/6? Would it be 2/6

Answers

No it would be 2/3 because the GCF of both of them is 2, so divide both the numerator and denominator by 2 and get 2/3

Fractions equal to 4/6 would be 8/12, or 2/3. Whatever you do to the top of the fraction, you have to do to the denominator. (or the bottom one) You divided the top of your fraction by 2 (and got 2/6) But you forgot to divide the denominator by 2 (to get 2/3.) Make sense?

4/n+9 = 2/7

What is the answer please!

Answers

Answer:

Step-by-step explanation:

Assuming the n+9 is in the denominator, start by cross multiplying.

multiply the n+9 by 2 and 4 by 7 to form the eqution 2n+18 = 28.

subtract the 18 from both sides to form the equation 2n = 10.

divide both sides by 2 to answer n = 5.

Another method is to think how to create equivalent fractions. to have 4/n+9 equal 2/7, the 2/7 is equivalent to 4/14. that means that n+9 is equivalent to 14, because the numerator are equal to each other. if n+9 = 14, then n = 5.

Does anyone know this