how do I solve this. Gil is reading a book that is 276 pages long. he read some of the book last week. he plans on reading 20 pages tomorrow. He would be 2/3 of the way through the book. how many pages has he read?

For this case we have the following variables:

x: number of free throws that Tessa made

y: total number of free throws

We now write the relationship of free throws.

We have then:

Simplifying the expression we have:

Answer:

The fraction of the free throws that she made is:

The correct answer is:

3/4.

Explanation:

27 out of 36 is written as 27/36. To simplify this, we divide numerator and denominator by common factors. Both are divisible by 9:

(27÷9)/(36÷9) = 3/4

It is given that two vertices of square are (0,0) and (4,2).

Now the problem is that you haven't given that whether these two vertices are adjacent vertices or opposite vertices of the square.

1. By Supposing that these two are adjacent vertices of Square

The third vertex will be at (-4,2) which lies in third quadrant.

Suppose the coordinate of fourth vertex be (x,y).

Mid point of line joining (4,2) and (-4,2) is{ [4+(-4)]/2,(2+2)/2} is (0,2).

Mid point of line joining (x,y) and (0,0) is (x/2,y/2).

Since diagonals of square bisect each other,

∵ x/2=0

⇒x=0

and

y/2=2

⇒y=4

So, The Coordinate of  fourth vertex is (0,4).

Now coming back to second condition if these are two opposite vertex of Square.

Let the third coordinate be (a,b).

Length of diagonal=

Now,let side of Square be A.

Then length of Diagonal of square =√2 A

⇒√2 A=2√5

⇒A =√10

As third vertex is (a,b).

Using distance formula

a² + b²=10  -------------(1)

(a-4)²+ (b-2)²=10  --------------(2)

Solving expression (1) and (2), we get

⇒a²+ b²=(a-4)² +(b-2)²

⇒2a + b =5

⇒b=5-2a

Putting the value of b in (1),we get

⇒a² +(5-2a)²=10

⇒a²+25+4a²-20a =10

⇒5a²-20a+15=0

⇒a² - 4a + 3=0

Splitting the middle term,we get

⇒(a-3)(a-1)=0

⇒a=3  ∧  a=1

we get b=5-2×1=3 and b=5-2×3=5-6=-1

So,the other vertex are (1,3) and(3,-1).

The other two vertices of the square are (-4, -2) and (-2, 4).

What are the other two vertices of a square with one vertex (0, 0) and another vertex (4, 2)?

To find the other two vertices of a square with one vertex at (0, 0) and another vertex at (4, 2), you can use the properties of a square, which has equal sides and right angles.

1. First, find the vector from the first vertex (0, 0) to the second vertex (4, 2). This vector represents one side of the square.

  Vector = (4 - 0, 2 - 0) = (4, 2)

2. Since the square has equal sides, you can move in the opposite direction of the vector to find the third vertex.

  Third Vertex = (0, 0) - (4, 2) = (-4, -2)

3. Now, to find the fourth vertex, you can rotate the vector by 90 degrees counterclockwise. To do this, swap the x and y components and negate the new x component:

  Fourth Vertex = (-2, 4)

So, the other two vertices of the square are (-4, -2) and (-2, 4).

Learn more on vertices here;

brainly.com/question/1217219

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