0.5 grams of sodium chloride is dissolved to make 0.05 liters of solution. How do I solve this?

Answer:

The patient requires a dose of 107.2 mg of gentamicin

Explanation:

A dosage of 1.75 mg per Kilogram body weight results in blood serum levels of 4.5 mcg/mL

This means that; 1.75 mg/ kg = 4.0 mcg/mL

Therefore, dosage of gentamicin in  mg/kg that will result in 4.5 mcg/mL blood serum level = (1.75 mg/Kg * 4.5 mcg/mL) / 4.0 mcg/mL

Dosageof gentamicin = 1.97 mg/Kg

1-lb = 0.453592 Kg

Weight of 120-lb patient in Kg = 120 * 0.453592 = 54.43 Kg

Dose in mg required by patient = 1.97 mg/Kg * 54.43 Kg = 107.2 mg

Therefore, the 120-lb patient requires a dose of 107.2 mg of gentamicin to result in a blood serum level of 4.5 mcg/mL

after a volcanic eruption is the answer

Mudflows of volcanic eruptions are the most dangerous, and are called lahars

Answer:

Melting point of aqueous solution = -10.32 °C

Explanation:

Where,

ΔT_f = Depression in freezing point

k_f = molal depression constant

m = molality

Formula for the calculation of molality is as follows:

density of water = 1 g/mL

density = mass/volume

Therefore,

mass = density × volume

volume = 3 L = 3000 mL

Mass of water = 1 g/mL × 3000 mL

                        = 3000 g

van't Hoff factor (i) for MgCl2 = 3

Substitute the values in the equation (1) to calculate depression in freezing point as follows:

Melting point of aqueous solution = 0 °C - 10.32 °C

                                                          = -10.32 °C

Answer:

The melting point of the solution is - 1.953 °C

Explanation:

In an ideal solution, the freezing point depression is computed as follows:

where:

is the freezing-point depression

is the cryoscopic constant, in this case is equal to 1.86

b is the molality of the solution

i is the van't Hoff factor, number of ion particles per individual molecule of solute, in this case is equal to 3

Molality is defined as follows:

b = moles of solute/kg of solvent

Moles of solute is calculated as follows:

moles of solute = mass of solute/molecular weight of solute

In this case there are 100 g of solute and its molecular weight is 35.5*2 + 24 = 95 g/mole. So, the moles are:

moles of solute = 100 g/(95 g/mol) = 1.05 moles

The mass of solvent is computed as follows:

mass of solvent = density of solvent * Volume of solvent

Replacing with the data of the problem we get:

mass of solvent = 1 kg/L*3 L = 3 kg

Finally, the molality of the solution is:

b = 1.05/3 = 0.35 mol/kg

Then, the freezing-point depression is:

The freezing-point depression is the difference between the melting point of the pure solvent (here water) and the melting point of the solution. We know that the the melting point of water is 0 °C, then:

melting point of water - melting point of the solution = 1.953 °C

melting point of the solution  = 0 °C - 1.953 °C = - 1.953 °C

Final answer:

The total number of atoms in 1.3 x 10^22 molecules of N(O)2 is 3.9 x 10^22 atoms since each molecule of N(O)2 consists of three atoms.

Explanation:

To answer the question of how many atoms there are in 1.3 x 10^22 molecules of N(O)2, one must be aware of the molecular composition of N(O)2. This molecule contains one nitrogen atom and two oxygen atoms, thus comprising three atoms in total. Consequently, to determine the total number of atoms, multiply the number of molecules by the number of atoms per molecule. Hence, the answer is 1.3 x 10^22 molecules * 3 atoms/molecule = 3.9 x 10^22 atoms.

Learn more about Atoms in a Molecule here:

brainly.com/question/15172278

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