Answer:
Solution A: 120 ounces
Solution B: 30 ounces
Step-by-step explanation:
Let's call A the amount of Solution A. Solution A is 70% salt
Let's call B the amount of Solution B. Solution A is 95% salt
The resulting mixture should have 75% salt and 150 ounces .
Then we know that the total amount of mixture will be:
Then the total amount of salt in the mixture will be:
Then we have two equations and two unknowns so we solve the system of equations. Multiply the first equation by -0.95 and add it to the second equation:
+
--------------------------------------
We substitute the value of A into one of the two equations and solve for B.
Answer:
We conclude that the average calorie content of a 12-ounce can is greater than 120 calories.
Step-by-step explanation:
We are given that a quality-control manager for a company that produces a certain soft drink wants to determine if a 12-ounce can of a certain brand of soft drink contains 120 calories as the labeling indicates.
Using a random sample of 10 cans, the manager determined that the average calories per can is 124 with a standard deviation of 6 calories.
Let = average calorie content of a 12-ounce can.
So, Null Hypothesis, :
120 calories {means that the average calorie content of a 12-ounce can is less than or equal to 120 calories}
Alternate Hypothesis, :
> 120 calories {means that the average calorie content of a 12-ounce can is greater than 120 calories}
The test statistics that would be used here One-sample t test statistics as we don't know about the population standard deviation;
T.S. = ~
where, = sample average calories per can = 124 calories
s = sample standard deviation = 6 calories
n = sample of cans = 10
So, test statistics = ~
= 2.108
The value of t test statistics is 2.108.
Now, at 0.05 significance level the t table gives critical value of 1.833 at 9 degree of freedom for right-tailed test. Since our test statistics is more than the critical values of t as 2.108 > 1.833, so we have sufficient evidence to reject our null hypothesis as it will in the rejection region due to which we reject our null hypothesis.
Therefore, we conclude that the average calorie content of a 12-ounce can is greater than 120 calories.
Q: The table shows the weights of apples at a grocery store. If this represents a proportional relationship, what is the weight of 12 apples? Remember to explain your answer :)
Step 1: So to start us off, because every 5 apples weighs 0.60 kilograms, we're going to divide 0.60 by 5 to get the weight of ONE apple.
0.60 divided by 5= 0.12
Now we know how much a single apple weighs in kilograms and we can move onto the next step.
Step 2: The next step is to times the weight of one apple by 12 because that would give us our answer for the weight in kilograms of 12 apples.
0.12 times 12=1.44
Hopefully, this is correct and helps you! Sorry if I made any errors, it would be best to go back and do the steps yourself just to make sure if that makes you feel any better. Good luck! xxoo
-Sav
Answer:
1.44kg
Step-by-step explanation:
If they are proportional then you can use the unitary method:
If 5 apples=0.6kg then 1 apple=0.12kg as this is 0.6/5 (because you divided the apples by 5 so you have to do the same to the kg)
then you can work out that 12 apples=1.44kg because 0.12*12 is 1.44 and you multiply by 12 as this is what you multiplied the apples by so (becasue they are proportional then you have to do the same to the kg)
hope this helps :)
Answer:
We can therefore conclude that the geographical distribution of hotline callers could be the same as the U.S population distribution.
Step-by-step explanation:
The null Hypothesis: Geographical distribution of hotline callers could be the same as the U.S. population distribution
Alternative hypothesis: Geographical distribution of hotline callers could not be the same as the U.S. population distribution
The populations considered are the Midwest, South, Northeast, and west.
The number of categories, k = 4
Number of recent calls = 200
Let the number of estimated parameters that must be estimated, m = 0
The degree of freedom is given by the formula:
df = k - 1-m
df = 4 -1 - 0 = 3
Let the significance level be, α = 5% = 0.05
For α = 0.05, and df = 3,
from the chi square distribution table, the critical value = 7.815
Observed and expected frequencies of calls for each of the region:
Northeast
Observed frequency = 39
It contains 18.1% of the US Population
The probability = 0.181
Expected frequency of call = 0.181 * 200 = 36.2
Midwest
Observed frequency = 55
It contains 21.9% of the US Population
The probability = 0.219
Expected frequency of call = 0.219 * 200 =43.8
South
Observed frequency = 60
It contains 36.7% of the US Population
The probability = 0.367
Expected frequency of call = 0.367 * 200 = 73.4
West
Observed frequency = 46
It contains 23.3% of the US Population
The probability = 0.233
Expected frequency of call = 0.233 * 200 = 46
Where observed frequency
Expected frequency
Calculate the test statistic value, x²
Since the test statistic value, x²= 5.535 is less than the critical value = 7.815, the null hypothesis will not be rejected, i.e. it will be accepted. We can therefore conclude that the geographical distribution of hotline callers could be the same as the U.S population distribution.
Answer:
87,010 cents is the SP.
Step-by-step explanation:
MP = $1400
VAT = 13%
Discount = 45%
so,
discount amount = 45% of MP
= 45% of $1400
= 45/100 * $1400
= 9/20 * $1400
= 9* $70
= $630
so,
MP - discount amount
= $1400 - $630
= $770(SP)
so,
VAT amount = 13% of SP
= 13% of $770
= 13/100 * $770
= $100.1
so,
SP + VAT
= $770 + $100.1
= $870.1
so,
$1 = 100 cents
$870.1 = 100*870.1
= 87,010 cents
Answer:
£32 in total for the top and two trousers
Step-by-step explanation:
The price for a top In the "cloth for you" shop= £10
The price for a bermuda trouser In the "cloth for you" shop= £12
There is a 20% discount on tops
The price If I bought one top and would trouser will be
(10-(0.2*10)) for the top
2(12) for the trouser
Total= (10-(0.2*10))+ 2(12)
Total = 10-2+24
Total = £32
So I spent £32 in total for the top and two trousers