Lets see,
.
Hope this helps.
Let's assume
that number is x
now, we are given
The difference between nine times a number an 7 is -70
nine times of that number is 9x
so, we can set up equation
now, we can solve for x
so, number is -7.........Answer
Graph, horizontal axis represents time and goes from zero to nine, vertical axis represents distance in miles and goes from zero to eight, graph is marked for Isabella at two and two and for Liam at four and two
Column A Column B
1.
Liam’s unit rate (bracelets per hour)
2.
Isabella’s unit rate (bracelets per hour)
3.
Number of bracelets Isabella can complete in 4 h
4.
Number of bracelets Liam can complete in 6 h
A.
3
B.
4
C.
1
D.1/2
E.
2
F.1 1/2
Answer:
x = - 3, x =
Step-by-step explanation:
Given
f(x) = 4x² + 5x - 21
To obtain the zeros, equate f(x) to zero, that is
4x² + 5x - 21 = 0
Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term
product = 4 × - 21 = - 84 and sum = + 5
The factors are + 12 and - 7
Use these factors to split the x- term
4x² + 12x - 7x - 21 = 0 ( factor the first/second and third/fourth terms )
4x(x + 3) - 7(x + 3) = 0 ← factor out (x + 3) from each term
(x + 3)(4x - 7) = 0
Equate each factor to zero and solve for x
x + 3 = 0 ⇒ x = - 3
4x - 7 = 0 ⇒ 4x = 7 ⇒ x =
You can find the zeros of the function f(x) = 4x² + 5x - 21 by setting the function equal to zero and solving for x using the quadratic formula. Upon solving, you get the zeros as -7/4 and 3.
To find the zeros of the quadratic function f(x) = 4x² + 5x - 21, you need to set the function equal to zero and solve for x. This means solving the equation 4x2 + 5x - 21 = 0. This is a quadratic equation that can be solved using the quadratic formula, x = [-b ± √(b² - 4ac)] / (2a).
Here, a = 4, b = 5, and c = -21. Substituting these values into the quadratic formula gives us x = [-5 ± √((5)² - 4*4*(-21))] / (2*4). Simplifying yields x = {-7/4, 3}.
#SPJ2