-4=-1b-(1/3)b
-4=-(4/3)b
-4/-(4/3)=b
b=3
-------------------------------
(1/2)3+(5/3)2
3/6+10/6=13/6
-23/3=13/6a
(-23/3)/(13/6)=a
a=-46/13
Use substitution to solve the linear system of equations and
determine how many chickens, x, and pigs, y there are.
Express the solution as an ordered pair (x,y).
Answer:
(6, 7)
Step-by-step explanation:
x+y= 13
2x+4y= 40 ⇒ x+2y = 20 ⇒ 13-y +2y= 20 ⇒ y= 20-13= 7
x= 13-y= 13-7= 6
chickens= 6
pigs= 7
To solve the problem, set up a system of equations using the given information. Solve one equation for a variable and substitute it into the other equation to find the values of the variables. Determine the number of chickens and pigs in the barn. The solution is (6, 7).
To solve this problem, we can set up a system of equations based on the given information. Let x represent the number of chickens and y represent the number of pigs. From the information given, we can write two equations: x + y = 13 (equation 1) and 2x + 4y = 40 (equation 2).
Using substitution, we can solve equation 1 for x and substitute it into equation 2:
Equation 1:
x + y = 13
x = 13 - y
Equation 2:
2(13 - y) + 4y = 40
26 - 2y + 4y = 40
2y = 14
y = 7
Now, substitute the value of y back into equation 1 to find x:
x + 7 = 13
x = 6
Therefore, there are 6 chickens and 7 pigs in the barn, which can be expressed as the ordered pair (6, 7).
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i don't understand what the question is .... but 3/7 is equal to 0.42857142857.
Have a great day :)
If gold coin weigh 20 grams. If the coin contains gold,copper and tin and in the ratio 4:3:1 then 10gm of gold is present in coin.
A ratio is an ordered pair of numbers a and b, written a / b where b does not equal 0.
Given,
A gold coin weigh 20 grams
the coin contains gold, copper and tin and in the ratio 4:3:1
We need to find the amount of gold in the coin.
Now let us add the ratio.
4x+3x+x=20
8x=20
Divide both sides by 8.
x=2.5
The amount of gold in coin is 4x.
4(2.5)=10 gm
Hence, 10 gm of gold is present in 20 grams of coin.
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