MATHEMATICS MIDDLE SCHOOL

A camera manufacturer spends $1,800 each day for overhead expenses plus $9 per camera for labor and materials. The cameras sell for $18each. a. How many cameras must the company sell in one day to equal its daily costs? b. If the manufacturer can increase production by 50
cameras per day, what would their daily profit be?

Answers

Answer 1
Answer:

Amount of money spent per day = $1800

Cost of overhead expenses per day for labor and materials = $9

Selling price of each camera = $18

a. Let us assume the number of cameras manufactured per day = x dollars

Then

Cost of cameras sold in 1 day = 18x

So

18x = 1800 + 9x

18x - 9x = 1800

9x = 1800

x = 200

From the above deduction, we can conclude that the number cameras sold per day is 200

b. Daily selling amount of 250 cameras = 250 * 18

                                                              = 4500 dollars

Daily manufacturing price of 250 cameras = 1800 + (9 * 250)

                                                                   = 4050 dollars

Then

Daily profit = 4500 - 4050

                 = 450 dollars

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Answers

Answer:

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Step-by-step explanation:

Which term can be used in the blank of 36x^3−22x^2−__ so the greatest common factor of the resulting polynomial is 2x? Select two options. 1) 2
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Answers

Answer:

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Step-by-step explanation:

Given : Expression  36x^3-22x^2-\_

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Answer:

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Step-by-step explanation:

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Answers

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Answers

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How to solve?

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Mass of  match box if it has 6 matches= 20-8(weight of matches)

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Learn more about mass brainly.com/question/14469428

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Each match has a mass of 2 g. This is because you must take the matchbox's total mass and subtract the mass of the box alone. You get 12, and then you divide by 6 to find the amount of each match

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