Here is a distribution of six observations, sorted in ascending order:4.7, 9.2, 10.9, 12.3, 16.6, 18.3The mean of this distribution is 12. What is the value of 6 sigma (xi -x with a line over it)

Answers

Answer 1

Answer:

Answer:

0 is the answer

Step-by-step explanation:

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To multiply or divide a number by 10,000, how many places should you move the decimal point?A : four
B : three
C : two
D : one

Answers

the answer is 4 ur welcome

The area of a square is 72. what is the longest straight line that can be drawn between any two points of the square

Answers

The longest straight line that can be drawn between any two points of a square is the one that includes the points on the opposite corners of the squares. To determine the length of this straight line, we must first determine the length of the square's side. Since the area of the square can be calculated by taking the square of the side, then

s^2 = 72
s = 6 sqrt(2)

Then, using the Pythagorean theorem, we will find c (the longest side of straight line of the square)

c^2 = a^2 + b^2

Upon substitution of the length of the square's side, we have
c^2 = (6 sqrt(2))^2 + (6 sqrt(2))^2
c^2 = 72+72
c = 72

The length of the longest line is 72.

Solve the following linear equation.

6(x + 2) = 30 x

Answers

Answer:

x=1/2

Step-by-step explanation:

6(x + 2) = 30x
6x + 12 = 30x
Subtract 6x from both sides
6x - 6x + 12 = 30x - 12
12 = 18x
Divide 18 from both sides
12/18 = 18x/18
12/18 = x

Multiple 8 by 10 5. How many zeros are before the decimal point in the product

Answers

your answer would 84.5

multiply the problem and then move your decimal over 1 to the left assuming it was at the end of your answer on the right your answer would be 840. move 1x to the left then becomes 84.0

1. x=1/(root3-root2). find rootx-(1/rootx) 2. if x=[root(a+2b)+root(a-2b)]/[root(a+2b)-root(a-2b]. show that bx^2-ax+b=0

Answers

Answer with explanation:

Ques 1)

$x=(1)/(√(3)-√(2))$

Now we are asked to find the value of:

$√(x)-(1)/(√(x))$

We know that:

$(√(x)-(1)/(√(x)))^2=x+(1)/(x)-2$

Also:

$x=(1)/(√(3)-√(2))$ could be written as:

$x=(1)/(√(3)-√(2))* (√(3)+√(2))/(√(3)+√(2))\n\n\nx=(√(3)+√(2))/((√(3))^2-(√(2))^2)$

since, we know that:

$(a+b)(a-b)=a^2-b^2$

Hence,

$x=(√(3)+√(2))/(3-2)\n\n\nx=√(3)+√(2)$

Also,

$(1)/(x)=√(3)-√(2)$

Hence, we get:

$(√(x)-(1)/(√(x)))^2=√(3)+√(2)+√(3)-√(2)-2\n\n\n(√(x)-(1)/(√(x)))^2=2√(3)-2\n\n\n√(x)-(1)/(√(x))=\sqrt{2√(3)-2}$

Hence,

$√(x)-(1)/(√(x))=\sqrt{2√(3)-2}$

Ques 2)

$x=(√(a+2b)+√(a-2b))/(√(a+2b)-√(a-2b))$

on multiplying and dividing by conjugate of denominator we get:

$x=(√(a+2b)+√(a-2b))/(√(a+2b)-√(a-2b))* (√(a+2b)+√(a-2b))/(√(a+2b)+√(a-2b))\n\n\nx=((√(a+2b)+√(a-2b))^2)/((√(a+2b))^2-(√(a-2b))^2)\n\n\nx=((√(a+2b))^2+(√(a-2b))^2+2√(a+2b)√(a-2b))/(a+2b-a+2b)\n\n\nx=(a+2b+a-2b+2√(a+2b)√(a-2b))/(4b)\n\n\nx=(2a+2√(a^2-4b^2))/(4b)\n\n\nx^2=((2a+2√(a^2-4b^2))/(4b))^2\n\n\nx^2=((2a+2√(a^2-4b^2))^2)/(16b^2)$

Hence, we have:

$x^2=(4a^2+4(a^2-4b^2)+8a√(a^2-4b^2))/(16b^2)\n\n\nx^2=(4a^2+4a^2-16b^2+8a√(a^2-4b^2))/(16b^2)\n\n\n\nx^2=(8a^2-16b^2+8a√(a^2-4b^2))/(16b^2)\n\n\nbx^2=(8a^2-16b^2+8a√(a^2-4b^2))/(16b)\n\n\nbx^2=(8a(a+√(a^2-4b^2))-16b^2)/(16b)\n\n\nbx^2=(8a(a+√(a^2-4b^2)))/(16b)-(16b^2)/(16b)\n\n\nbx^2=(a(a+√(a^2-4b^2)))/(2b)-b\n\n\nbx^2=ax-b\n\n\ni.e.\n\n\nbx^2-ax+b=0$

1. x = 1/ ( $√(3) - √(2))$ = $√(3)+ √(2)$ ;
( $√(x) -1/ √(x) )^(2) = x + 1/x - 2 =$ =

In one day, Annie traveled 5 times the sum of hours Brian traveled 2. Together they traveled 20 hours. Find the number of hours each person travels

Answers

20÷6=3 1/3
soooo
Brian:3 1/3
Annie:16 2/3

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