If the core of a supernova explosion contains three or more solar masses of matter, the core will most likely become a _____.

Answers

Answer 1
Answer: The correct answer to the question you gave above would be a black hole. If the core of a supernova explosion contains three or more solar masses of matter, the core will most likely become a black hole. 

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Each of 100 identical blocks sitting on a frictionless surface is connected to the next block by a massless string. The first block is pulled with a force of 100 N. What is the tension in the string connecting block 100 to block 99? What is the tension in the string connecting block 50 to block 51?

Answers

We have that for the Question "What is the tension in the string connecting block 100 to block 99? What is the tension in the string connecting block 50 to block 51?"

it can be said that

  • The tension in the string connecting block 100 to block 99 = 1N
  • The tension in the string connecting block 50 to block 51 = 50N

From the question we are told

Each of 100 identical blocks sitting on a frictionless surface is connected to the next block by a massless string. The first block is pulled with a force of 100 N.

Assuming mass of each block is 1 kg

The equation for the force is given as

F = ma\n\na = (F)/(m)\n\n = (100)/(100*1)\n\n = 1 m/s^2

Now, between block 100 and 99,

F = ma\n\nF = 1*1 \n\n= 1 N

Now between block 50 and 51. There are 50 blocks behind 51 st block,  so,

m = 50 Kg\n\na = 1 m/s2 (assuming all blocks accelerate at same rate)\n\nF = 50 * 1\n\nF= 50 N

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Answer:

The tension in the string connecting block 50 to block 51 is 50 N.

Explanation:

Given that,

Number of block = 100

Force = 100 N

let m be the mass of each block.

We need to calculate the net force acting on the 100th block

Using second law of newton

F=ma

100=100m* a

ma=1\ N

We need to calculate the tension in the string between blocks 99 and 100

Using formula of force

F_(100-99)=ma

F_(100-99)=1

We need to calculate the total number of masses attached to the string

Using formula for mass

m'=(100-50)m

m'=50m

We need to calculate the tension in the string connecting block 50 to block 51

Using formula of tension

F_(50)=m'a

Put the value into the formula

F_(50)=50m* a

F_(50)=50*1

F_(50)=50\ N

Hence, The tension in the string connecting block 50 to block 51 is 50 N.

What forces are acting on a book lying on the table? Are action-reaction forces involved in this situation?

Answers

There is a weight force acting on the book downwards. There is a normal contact force also on the book upwards. These are equal and opposite. These two force are NOT an action-reaction couple (they are different types, they both act on the book)

Korey is planning to open a comic book store. In his first year of operation, Korey expects to average $1,000 of profit each month. He then expects profits to increase by 6% each year for the next 4 years. How much does Korey expect to make in profits in his fifth year of operation?

Answers

First year profit: $1000*12 = $12,000
Second year profit: $12,000 * 1.06
Third year profit: $12,000 * 1.06^2
Fourth year profit: $12,000 * 1.06^3
Fith year profit: $12,000 * 1.06^4 =$15,149.72
:

In this exercise we have to use the knowledge of finance to calculate the  profits that Korey expect to make is $15,149.72.

So organizing the information given in the statement we find that:

  • average $1,000 of profit
  • 6% each year for the next 4 years

Doing these calculations we find that:

1000*12 = $12,000\n12,000 * 1.06^1\n12,000 * 1.06^2\n12,000 * 1.06^3\n12,000 * 1.06^4 =$15,149.72

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The effects of agriculture and industry can be more harmful with the further loss of wetlands.

Answers

Yes, it is true that the effects of agriculture and industry can be more harmful with the further loss of wetlands since industry usually requires large amounts of land. 

Answer:trueeeeeeeeee

Explanation:

a horse moves a sleigh 1.00 kilometers by applying a horizontal 2000 Newton force on its harness for 45 minutes. what is the power of the horse?

Answers

--  If 2,000 newtons of force were applied through a distance of 1,000 meters,
then 2,000,000 newton-meters = 2,000,000 joules of work were done.

-- 45 minutes = (45 x 60) = 2,700 seconds

-- Power = (work) / (time) = (2,000,000 j) / (2,700 s) = 740.74 watts

Interestingly, that's almost exactly 1 horsepower.  (0.99295... of 746 watts)

a skier is gliding along 3.0 m/s on horizontal, frictionless snow. he suddenly starts down a 10 degrees incline. his speed at the bottom is 15 m/s. what is the lenght of the incline? how long does it take him to reach the bottom?

Answers

... find length
(way 1) determine acceleration using force
only force act on skier is mg vertically. spilt vector we get force along the incline = mgsin(10) and f= ma so
ma = mgsin(10) or a = gsin(10)
a (along the incline)= gsin(10) = 10sin(10) = 1.74
v^2 = u^2 + 2as
15^2 = 3^2 + 2(1.74)s
s = 62.06 m

(way 2) using conservation of energy
energy (KE+PE) on top = energy at bottom
0.5m3^2 + mgh = 0.5m15^2 +0
h (height of incline) = (112.5 - 4.5)/10 = 19.8 m
length of incline = h/sin(10) = 62.2 m ; trigonometry

... find time
s = (u+v)t/2
t = 2s/(u+v) = 2(62.2)/(3+15) = 6.91 s