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PLEASE ANSWER ASAP! MUST BE WITH WITH WITH WITH WWWWWIIIIIIIITTTTTHHHH - 1

Answers

Answer 1
Answer: area=legnth tmes width
split it up
dark face=14 times 6
front bottom rectangle=14 time 8 (2 of them, front and back)
bottom 14 times 6
very top square 6 times 6
squaer that we can't see 6 times6
side squares 6 times 6
top 8 times 6

total (sorr if confusing)
632

answer is C

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What is 3 ft. Times 6 1/2 in. Times 6 1/2 in.?

Answers


1 ft = 12 inches

3 ft =  36 inches

                              (3 ft) x (6.5 inches)

                           = (36 inches) (6.5 inches)

                           =  234 square inches

8 kg of potatoes and 5 kg of carrots cost $28 whereas 2 kg of potatoes and 3 kg of arrot cost $11.20.what is the cost of 1 kg of each item

Answers

1 kg of potatoes costs  x, 1 kg of carrots costs y.

8x+5y=28 | :(-4)
2x+3y=11,2

-2x-1,25y=-7
2x+3y=11,2

3y-1,25y=11,2-7
1,75y=4,2
y=2,4

1 kg of carrots costs $2,4.

1 kg of potatoes costs:
2x+3*2,4=11,2
2x+7,2=11,2
2x=11,2-7,2
2x=4
x=2
kg of potatoes costs $2

Whats is the answer to (x+4) (x+2)

Answers

x^2 + 6x + 8 

solve by using FOIL

Can someone help me with this problem...
#20

Answers

3/12, 1/3, 2/5, 4/9, 5/8, 2/3, 3/4, 5/6

Help!What is the greatest common factor of 42, 60 and 78?
OA) 2
OB) 6
OC) 12
OD 24

Answers

Answer:

The greatest common factor of 42, 60 and 78 is  6.

Step-by-step explanation:

The given numbers are : 42, 60 and 78

On Prime Factorization of the given terms, we get:

42 = 2 x 3 x 7

60 = 2 x 2 x 3 x 5

78  = 2 x 3 x 13

The common factors to all these three terms is   2 x 3  = 6

Hence, the greatest common factor of 42, 60 and 78 is  6.

What is the solution to the system?-2x + y + 6z = 1
3x + 2y + 5z = 16
7x + 3y – 4z = 11

Answers

Answer:

x = 4, y = -2, z = 3

Step-by-step explanation:

\left\{\begin{array}{ccc}-2x+y+6z=1&(1)\n3x+2y+5z=16&(2)\n7x+3y-4z=11&(3)\end{array}\right\n\n(1)\n-2x+y+6z=1\qquad\text{add}\ 2x\ \text{to both sides}\ny+6z=2x+1\qquad\text{subtract}\ 6z\ \text{from both sides}\ny=2x-6z+1\n\n\text{Substitute it to (2) and (3):}\n\n\left\{\begin{array}{ccc}3x+2(2x-6z+1)+5z=16\n7x+3(2x-6z+1)-4z=11\end{array}\right\qquad\text{use the distributive property}\n\n

\left\{\begin{array}{ccc}3x+4x-12z+2+5z=16&\text{subtract 2 from both sides}\n7x+6x-18z+3-4z=11&\text{subtract 3 from both sides}\end{array}\right\n\left\{\begin{array}{ccc}7x-7z=14&\text{divide both sides by 7}\n13x-22z=8\end{array}\right\n\left\{\begin{array}{ccc}x-z=2&\text{multiply both sides by (-13)}\n13x-22z=8\end{array}\right

\underline{+\left\{\begin{array}{ccc}-13x+13z=-26\n13x-22z=8\end{array}\right}\qquad\text{add both sides of the equations}\n.\qquad\qquad-9z=-18\qquad\text{divide both sides by (-2)}\n.\qquad\qquad \boxed{z=2}\n\n\text{Put it ot the equation}\ x-z=2:\nx-2=2\qquad\text{add 2 to both sides}\n\boxed{x=4}\n\n\text{Put the values of}\ x\ \text{and}\ z\ \text{to the equation}\ y=2x-6z+1:\n\ny=2(4)-6(2)+1\ny=8-12+1\n\boxed{y=-3}