Answer:
It’s b
Step-by-step explanation:
The coordinates of the midpoint of two points A and B are the averages of the corresponding coordinates of A and B.
So if one point is (a, b) and another point is (c, d), the point exactly between them has coordinates ((a+b)/2, (c+d)/2).
In this example, the points
A(-3a, b)
B(3a, b)
have midpoint
F((-3a+3a)/2, (b+b)/2) = F(0, 2b/2) = F(0, b)
solve for y
please I need help
Answer:
The answer is y = -2.
Step-by-step explanation:
To start, you need to cross multiply to solve.
3/y = 6/(y -2)
y*6 = 3*(y -2)
6y = 3y - 6
3y = -6
y = -2
f(x) = 4(x + 6)^2+ 5
Substitute numerical values into the equation for a, b, and c.
F(x) = ax^2 + bx + c
The numerical values in the equation for a, b, and c will be 4, 48, and 149, respectively.
A function is an assertion, concept, or principle that establishes an association between two variables. Functions may be found throughout mathematics and are essential for the development of significant links.
The quadratic equation is given as ax² + bx + c = 0. Then the degree of the equation will be 2.
The quadratic function is given below.
f(x) = 4(x + 6)²+ 5
Convert the equation into a standard form. Then we have
f(x) = 4(x + 6)²+ 5
f(x) = 4(x² + 12x + 36)+ 5
f(x) = 4x² + 48x + 144 + 5
f(x) = 4x² + 48x + 149
The numerical values in the equation for a, b, and c will be 4, 48, and 149, respectively.
More about the function link is given below.
#SPJ5
Answer:
f(x) = 4x² + 48x + 149
Step-by-step explanation:same as the one above me.