64 calls in 3 hours whats the ratio rate per hour

Answers

Answer 1
Answer: 64 calls in 3 hours

Divide both numbers by 3 to find the unit rate (number of calls in 1 hour)

64/3 calls in 1 hour or21 1/3 as a mixed number

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What is the quotient of 6.39 divided by 0.3?
5x – 4 = x - 16solve the equation

A certain liquid has a density of 2.67 g/cm3. 30.5 mL of this liquid would have a mass of ________ Kg. 0.0114
11.4
0.0814
0.0875 81.4

Answers

Answer:

One ml is equal to a cm3, then

m=2.67g/cm3*30.5cm3

m=81.435g

If we divide this quantity by 1000 to pass this to Kg we get:

m=81.435/1000=0.081435kg

Step-by-step explanation:

Remember the formula of density is density=mass/volume, if we solve for mass we get:

mass=density*volume

50-yards change it to miles ?

Answers

Ohh okay

so you would do 1760/50
then 3600/5.8

then take the two answers and divide them by each other...

1760/50=35.2
3600/5.8=620.689655172

620.689655712/35.2= 17.6332288401

Are the expressions (4x)^2 and 4x^2 equal in value? How would you explain your answer?

Answers

understand pemdas
parenthasees
exponenets
multiiplication or dividsion
additon or subtraction


(4x)^2=4x times 4x
4x^2=4 times x times x=4(x^2)

(4x)^2=16x^2
4x^2=4(x^2)
values are not equal
(just for fun: 4x^2=(2x)^2)


"Among 40 students, 20 liters of juice was served. How much juice did each student get?"

Answers

Answer:

How much juice did each student get?"

40/20=2

each student received 2L of juice

Step-by-step explanation:

Each student got 1/2 a litre or 500 ml sa 20 divided by 40 equals half

Graph the equation 5y-3x=-15

Answers

5y - 3x = - 15

isolate y for 5y - 3x = -15

y = -15 + 3x / 5

x - axis interception point of  -15 + 3x / 5  ( 5,0 )

y - axis interception point of 
 -15 + 3x / 5   ( 0, -3)

attached image.

hope this helps!

5y-3x=-15y=(-15+3x)/5
y=3/5x-3

When x = 0  y =-3
When y = 0  x = 5
When x = 10 y = 3
When x = -5  y = - 6
When x = -10 y = -9

An observation deck extends 314 feet out above a valley. The deck sits 264 feet above the valley floor. If an object is dropped from the observation​ deck, its height h in​ feet, after t​ seconds, is given by h equals negative 16 t squared plus 264. How long will it take for the object to be 8 feet above the valley​ floor?

Answers

Final answer:

Using the quadratic equation h = -16t² + 264 which represents the object's height after time, we find that it will take 4 seconds for the object to reach 8 feet above the valley floor.

Explanation:

In this case, you're asked to find out how much time it takes for an object dropped from an observation deck to drop to a point 8 feet above the valley floor. The height h, in feet, after time t, in seconds, is represented by the quadratic equation h = -16t² + 264. Set the equation equal to desired height, which is 8 feet in this case. So, you have -16t² + 264 = 8. Rearranging, you get -16t² = 8 - 264, or -16t² = -256. Divide by -16 yields, t² = 16. The principal square root of 16 is t = 4.

Therefore, it will take 4 seconds for the object to be 8 feet above the valley floor.

Learn more about Quadratic Equations here:

brainly.com/question/30098550

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