Answer:
See attached picture.
Step-by-step explanation:
To graph the equation, use the slope intercept form of the line to identify the slope and y-intercept.
y = -x + 1 y = mx+b
m=-1 and b=1
This means start at 1 on the y-axis and plot a point. From this point (0,1), move down 1 unit and to the right 1 unit. Plot this point (0,1). Connect the two points.
B). (6,8),(0,0),(18,24)
C). (3,6),(4,8),(9,4)
D). (1,1),(2,1),(3,3)
Answer: Option B.
Step-by-step explanation:
By definition, the graph of a proportional relationships is a straight line that passes through the origin (Remember the the origin is at ).
Then, the equation have the following form:
Where "k" is the constant of proportionality (or its slope)
Then, since the Sara graphs a line that represent a proportional relationship, you can conclude that the line must pass through the point .
Then:
The set of points in Option A could not be on that line, because when
The set of points (Given in Option B) could be on the line that Sara graphs, because it has the point
For the set of points shown in Option C and Option D, you can check if the slope is constant:
Since the slope is not constant, this set of ponts could not be on the line.
Since the slope is not constant, this set of ponts could not be on the line.
Set of points that could be on the line that Sara graphs are:
Option B). (6,8) , (0,0) , (18,24)
Solving linear equation mean calculating the unknown variable from the equation.
Let the linear equation : y = mx + c
If we draw the above equation on Cartesian Coordinates , it will be a straight line with :
m → gradient of the line
( 0 , c ) → y - intercept
Gradient of the line could also be calculated from two arbitrary points on line ( x₁ , y₁ ) and ( x₂ , y₂ ) with the formula :
If point ( x₁ , y₁ ) is on the line with gradient m , the equation of the line will be :
Let us tackle the problem.
This problem is about Directly Proportional.
If (x₁ , y₁ ) and (x₂ , y₂) are on the line that represent a proportional relationship, then :
Let:
(2,4) ⇒ (x₁ , y₁)
(3,9) ⇒ (x₂ , y₂)
→ not proportional
Let:
(6,8) ⇒ (x₁ , y₁)
(18,24) ⇒ (x₂ , y₂)
→ proportional
Let:
(3,6) ⇒ (x₁ , y₁)
(9,4) ⇒ (x₂ , y₂)
→ not proportional
Let:
(1,1) ⇒ (x₁ , y₁)
(2,1) ⇒ (x₂ , y₂)
→ not proportional
Grade: High School
Subject: Mathematics
Chapter: Linear Equations
Keywords: Linear , Equations , 1 , Variable , Line , Gradient , Point
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What is the constant of proportionality?