MATHEMATICS HIGH SCHOOL

If sin x = cos 54 degrees what is value x

Answers

Answer 1

Answer:

Answer:

The Answer is 36 for anyone looking.

Answer 2

Answer: 54x to the root of 98

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In a right triangle, angle C measures 40. the hypotenuse of the triangle is 10 inches long. what is the approximate length of the side adjacent to angle C

Answers

Since angle C is not 90 degrees, it's one of the acute angles
in the right triangle.

   (The side adjacent to angle C ) divided by (hypotenuse)

is the cosine of angle C .

(adjacent) / (10 inches) = cos(40 degrees)

Multiply each side by (10 inches):

      Adjacent side = (10 inches) x cos(40) =

(10 inches) x 0.766 =

7.66 inches (rounded)

The approximate length of the side adjacent to angle $C$ is $\boxed{{\mathbf{7}}.7{\mathbf{ inches}}}$ .

Further explanation:

The trigonometry ratio used in the right angle triangles.

The cosine ratio can be written as,

$\cos \theta = (length\ of\ the\ side\ adjacent\ to\ \theta )/(hypotenuse)$

Here, base is the length of the side adjacent to angle $\theta$ and hypotenuse is the longest side of the right angle triangle where the length of side opposite to angle $\theta$ is perpendicular that is used in the sine ratio.

Step by step explanation:

Step 1:

The attached right angle triangle can be observed from the given information.

First define the hypotenuse and the base of the triangle.

The side $BC$ is adjacent to angle $C$ and the side $AC$ is the hypotenuse of $\Delta ABC$ .

Therefore, the ${\text{length of the side adjacent to C}}=BC$ and ${\text{hypotenuse}}=10$ .

Step 2:

Since, the cosine ratio is $\cos \theta = (length\ of\ the\ side\ adjacent\ to\ \theta )/(hypotenuse)$

Now put the value ${\text{length of the side adjacent to C}}=BC$ and ${\text{hypotenuse}}=10$ in the cosine ratio.

$\begin{aligned}\cos C&=\frac{{BC}}{{10}}\n{\text{co}}s40&=\frac{{BC}}{{10}}\n0.766&=\frac{{BC}}{{10}}\nBC&=7.66\n\end{aligned}$

Therefore, the approximate length of the side adjacent to angle $C$ is $7.66{\text{ inches}}$ .

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Answer details:

Grade: High school

Subject: Mathematics

Chapter: Trigonometry

Keywords: Distance, Pythagoras theorem, base, perpendicular, hypotenuse, right angle triangle, units, squares, sum, cosine ratio, adjacent side to angle, opposite side to angle.

Which would be appropriate compatible numbers to use to estimate (19 4/5)(4/6)

Answers

Answer:

Approximately 10

Step-by-step explanation:

19 / 5 Approximately 4

4 * 4 = 16

16 * 4 / 64

64 / 6 * = Approximately 10 / 10.6 ish

Actual Answer is 10.133

A map uses a scale of 2 cm = 50 kilometers. On the map, two cities are 9 cm apart, how far apart are they in real life?

Answers

Answer:

they are in 225kilometers apart.

hope it helps.

The work of a student to solve a set of equations is shown: Equation 1: m = 8 + 2n
Equation 2: 4m = 4 + 4n

Step 1: −4(m) = −4(8 + 2n) [Equation 1 is multiplied by −4.]
4m = 4 + 4n [Equation 2]
Step 2: −4m = −32 − 8n [Equation 1 in Step 1 is simplified.]
4m = 4 + 4n [Equation 2]
Step 3: −4m + 4m = −32 − 8n + 4n [Equations in Step 2 are added.]
Step 4: 0 = −32 − 4n
Step 5: n = −8

In which step did the student first make an error?

Step 1
Step 2
Step 3
Step 4

Answers

it might be step 4 where it got dropped by step 3

Please help me this is due in 2 hours you need to explain your answer plzzzzzz???????!!!!!!!

Answers

Answer:

1) one muffin costs $1.50

one quart of milk costs $3.00

2) 10 videos, 30 CDs

Step-by-step explanation:

m = cost of one muffin

q = cost of one quart of milk

System of equations:

3m + 1q = 7.5

8m + 2q = 18

I multiplied the first equation by -2 to eliminate the 'q' values

-6m - 2q = -15

+ 8m + 2q = 18

2m = 3

m = 3/2

find 'q':

3(3/2) + q = 7.5

9/2 + q = 15/2

q = 6/2 or 3

c = # of CDs sold

v = # of videos sold

System of equations:

c + v = 40

4c + 6v = 180

I solved first equation for 'c' to get c = 40 - v

4(40-v) + 6v = 180

160 - 4v + 6v = 180

2v = 20

v = 10

10 + c = 40

c = 30

Please help with question 2! BRAINLIEST to correct answer!!!

Answers

Answer:

B: (-infinity, 4]

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