When you derive a function from another using the transformation
you're translating the graph of the parent function f(x) horizontally.
More specifically, you translate the graph k units to the left if k is positive, k units to the right if k in negative.
So, starting from the graph of f(x), you have that the graph of
is the same graph of f(x), but shifted 3 units to the left.
Answer:
sss
Step-by-step explanation:
Her father's computer cost $2,000
- Katrina saved $200 to purchase her tablet
This means Katrina saved an amount of $200 to be able to purchase the tablet which cost $200
- Her father spent 10 times as much money time buy his new computer
Katrina father also purchased a new computer which cost is 10 times the amount that Katrina saved to purchase her tablet
- How much did her father's computer cost?
Her father's computer cost $2,000 ($200 X 10 times)
See related question here brainly.com/question/1787018
Answer:
2 successes = 80/243
0 successes = 32/243
at least 3 successes = 51/243
Step-by-step explanation:
Lets suppose we had the following sequence of 5 throws:-
2 or 3, 2 or 3 , then NOT 2 or 3 on last 3 throws
Probability of this is
1/3 * 1/3 * 2/3 * 2/3 * 2/3 = 8/243
There are (5*4) / 2 = 10 ways of having this result ( that is the number of combinations of 2 from 5 = 5C2 ).
So Prob(2 successes) = (8/243) * 10 = 80/243
Prob ( No successes) = (2/3)^5 = 32/243
Probability of 3 successes = 1/3 * 1/3 * 1/3 * 2/3 * 2/3 * 5C3
4/243 * 10 = 40 / 243
Probability of 4 successes = (1/3)^4 * 2/3 * 5C4
= 10/243
Probability of 5 success = (1/3)^5 = 1 / 243
Prob(at least 3 successes) = 51/243
Answer:
2 successes = 80/243
0 successes = 32/243
at least 3 successes = 51/243
Step-by-step explanation:
Lets suppose we had the following sequence of 5 throws:-
2 or 3, 2 or 3 , then NOT 2 or 3 on last 3 throws
Probability of this is
1/3 * 1/3 * 2/3 * 2/3 * 2/3 = 8/243
There are (5*4) / 2 = 10 ways of having this result ( that is the number of combinations of 2 from 5 = 5C2 ).
So Prob(2 successes) = (8/243) * 10 = 80/243
Prob ( No successes) = (2/3)^5 = 32/243
Probability of 3 successes = 1/3 * 1/3 * 1/3 * 2/3 * 2/3 * 5C3
4/243 * 10 = 40 / 243
Probability of 4 successes = (1/3)^4 * 2/3 * 5C4
= 10/243
Probability of 5 success = (1/3)^5 = 1 / 243
Prob(at least 3 successes) = 51/243