A rancher has 200 feet of fencing to enclose two adjacent corralsa.what dimensions should be used so that the enclosed area will be maximum b)what is the maximum area?
Answers
Answer:
a) Each corral should be 33⅓ ft long and 25 ft wide
b) The total enclosed area is 1666⅔ ft²
Step-by-step explanation:
I assume that the corrals have identical dimensions and are to be fenced as in the diagram below
Let x = one dimension of a corral
and y = the other dimension
(a) Dimensions to maximize the area
The total length of fencing used is:
4x + 3y = 200
4x = 200 – 3y
x = 50 - ¾y
The area of one corral is A = xy, so the area of the two corrals is
A = 2xy
Substitute the value of x
A = 2(50 - ¾y)y
A = 100 y – (³/₂)y²
This is the equation for a downward-pointing parabola:
A = (-³/₂)y² + 100y
a = -³/₂; b = 100; c = 0
The vertex (maximum) occurs at
y = -b/(2a) = 100 ÷ (2׳/₂) = 100 ÷ 3 = 33⅓ ft
4x + 3y = 100
Substitute the value of y
4x + 3(33⅓) = 200
4x + 100 = 200
4x = 100
x = 25 ft
Each corral should measure 33⅓ ft long and 25 ft wide.
Step 2. Calculate the total enclosed area
The enclosed area is 50 ft long and 33⅓ ft wide.
A = lw = 50 × 100/3 = 5000/3 = 1666⅔ ft²
Final answer:
The maximum area is achieved when the shared fence is 50 feet and the other two sides are 75 feet each, yielding a maximum area of 3750 square feet.
Explanation:
This problem can be solved by the principles of calculus. Assuming that the two corrals share a common side, we can say the total length of fencing is divided into two lengths (x and y). The optimization problem can be formed as follows:
- x = length of the common fence
- y = length of the other sides
Since the total length available is 200 feet, 2y + x = 200. The area A = xy. Substitute y=(200-x)/2 into the area formula to get a quadratic A = x(200-x)/2. This graph opens downwards, meaning the vertex is the maximum point. The x-coordinate of the vertex of a quadratic given in standard form like Ax^2 + Bx + C is -B/2A. Therefore, x = -B/2A = 200/(2*2) = 50. Substitute x back into y = (200-2x)/2 to get y = 75. So, the maximum area is achieved with a common side of 50 feet and the other sides being 75 feet each.
The maximum area A can be found by substituying these values back into the area formula: A = 75*50 = 3750 square feet.
Learn more about Optimization here:
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The formula for finding the perimeter of a circle:
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This statement is actually false.
I have provided proof and wish you all the best (grade).