Answer:
Angles of △EFQ:
m<EFQ = 100°
m<EQF = 14°
m<FEQ = 66°
Step-by-step explanation:
ED is the diameter of the circle O
so m<EFD = 1/2 (180) = 90°
Given m∠DFQ = 10°
△EFQ
m<EFQ = m<EFD + m∠DFQ = 10° + 90° = 100°
arc EF = 28°,
so m<EQF = 1/2 (28) = 14°
m<FEQ = 180 - ( 100° + 14°) = 66°
Answer:
m<EFQ = 100°
m<EQF = 14°
m<FEQ = 66°
Answer:
To find the number of boards that must be sold to break even, we need to set the revenue equal to the cost and solve for x.
Given:
Revenue R = 40x
Cost C = 30x + 1000
Since the break-even point is when revenue equals cost, we have the equation:
40x = 30x + 1000
To solve for x, we subtract 30x from both sides of the equation:
40x - 30x = 30x + 1000 - 30x
Simplifying:
10x = 1000
Dividing both sides by 10:
x = 100
Therefore, to break even, 100 computer boards must be sold.
To find the amount of money needed to produce the break-even number of boards, we substitute the value of x into the cost equation:
C = 30x + 1000
C = 30 * 100 + 1000
C = 3000 + 1000
C = 4000
Therefore, $4000 is needed to produce the break-even number of boards.
Step-by-step explanation:
Answer: 8
Step-by-step explanation:
2/3 divided by 1/12
2/3 * 12/1
24/3=8
hope i helped angel!
Answer:
I think it would be 8
Step-by-step explanation:
Divide 2/3 by 1/12.
(2/3) / (1/12) = 2/3 * 12/1 = 24/3 = 8
Answer:
Carbon-14 will take 19,035 years to decay to 10 percent.
Step-by-step explanation:
Exponential Decay Function
A radioactive half-life refers to the amount of time it takes for half of the original isotope to decay.
An exponential decay can be described by the following formula:
Where:
No = The quantity of the substance that will decay.
N(t) = The quantity that still remains and has not yet decayed after a time t
= The decay constant.
One important parameter related to radioactive decay is the half-life:
If we know the value of the half-life, we can calculate the decay constant:
Carbon-14 has a half-life of 5,730 years, thus:
The equation of the remaining quantity of Carbon-14 is:
We need to calculate the time required for the original amout to reach 10%, thus N(t)=0.10No
Simplifying:
Taking logarithms:
Solving for t:
Carbon-14 will take 19,035 years to decay to 10 percent.
Approximately 23,083 years will pass for carbon-14 to decay to 10 percent of its original amount.
To find out how long it will take for carbon-14 to decay to 10 percent of its original amount, we can use the concept of exponential decay. The formula for calculating the amount of a radioactive substance remaining after a certain time can be expressed as:
A(t) = A₀ * (1/2)ˣ/ₓ₂
Where:
A(t) is the amount of carbon-14 at time t
A₀ is the initial amount of carbon-14
t₁/₂ is the half-life of carbon-14 (5,730 years)
t is the time we want to find (in years)
We want to find t when A(t) is equal to 0.10 * A₀ (10 percent of the original amount). So, the equation becomes:
0.10 * A₀ = A₀ * (1/2)ˣ/₅₇₃₀
Now, we can cancel out A₀ on both sides of the equation:
0.10 = (1/2)ˣ/₅₇₃₀
To isolate t, we can take the logarithm of both sides (base 2) since the half-life is used in the equation:
log₂(0.10) = t / 5730
Now, we can solve for t:
t = 5730 * log₂(0.10)
To know more about decay here
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Answer:
5
Step-by-step explanation:
let the consecutive odd numbers be n and n + 2 , then
n(n + 2) = n² + 10 , that is
n² + 2n = n² + 10 ( subtract n² from both sides )
2n = 10 ( divide both sides by 2 )
n = 5
That is the smaller number is 5
…, 1/4, 1/2, 1, 2,…
…, 1/72, 1/36,1/18, 1/9, …
…, 8, 4, 2, 1, …