In The Odyssey, Agamemnon becomes a symbol of warning against marital infidelity, and Amphimedon illustrates the consequences of arrogance and failed ambition.
In Homer's The Odyssey, the deaths of both Agamemnon and Amphimedon have drastically changed their characters. Agamemnon, the once lord and great warrior, is portrayed post-mortem as a bitter figure, dwelling on his betrayal and murder by his wife Clytemnestra. His death has transformed him into a character symbolizing a warning against marital infidelity. Amphimedon, after his death, is portrayed in the halls of Hades, as a resentful spirit recounting the tales of their defeat at the hands of Odysseus and his son. He becomes an embodiment of regret and failed ambition. These characters' transformation elucidates the theme of the consequences of one's actions, both in life and after death.
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external conflict
exposition
internal conflict
.
Question 3
Captain Sawyer vs. the Yankee guard can be described as what kind of conflict?
character
external conflict
exposition
internal conflict
.
Question 4
Which statement is false?
The Yankee guard dies.
Captain Sawyer escapes.
Ma never leaves the house.
Mary becomes a heroine.
.
Question 5
Where is Mary's father?
out riding Santo, the horse
visiting his mother
fighting in the war
dead
.
Question 6
Which conflict does not exist in this story?
Mary vs. Ma
South vs. North
Mary vs. Captain Sawyer
Reality vs. Fiction
Answer:
????
Explanation:
about 2700 kcal/day
about 2100 kcal/day
about 4000 kcal/day
Answer: About 3100kcal/day
Explanation:
Gender - male
Height - 5 feet 10 inches (1.778m)
Weight - 155 pounds (70.307kg)
Age - 19
Session - 60 minutes / session atleast 5days a week (Active Physical Activity(PA) bracket)
Active PA factor = 1.27
Estimated Energy Requirement (kcal/day) =
Total Energy Expenditure + Energy Deposition
Adults 19 years and older - Men
EER = 662 - (9.53 x age [y]) + PA x { (15.91 x weight [kg]) + (539.6 x height [m]) }
EER = 662 - (9.53 × 19) + PA × {(15.91 × 70.307) + (539.6 × 1.778)}
EER = 662 - 181.07 + PA × { 1118.584 + 959.4088}
EER = 480.93 + PA × (2077.9928)
EER = 480.93 + 1.27(2077.9928)
EER = 480.93 + 2639.050856
EER = 3119.9808
EER is about 3100kcal/day
Answer:
about 3100 kcal/day (A)
Explanation:
Age = 19yrs
Height = 5 feet 10 inches tall = 5.833 feet = 1.78m
Weight = 155 pounds = (155/2.2)kg = 70.45kg
The desired BMI(body mass index) is 18.5 to 24.9 (128.7pounds to 173.4 pounds).
Since his weight is 155 pounds, it falls under the desired BMI.
EER for Adults 19 years and older - Men
EER = 661.8 - (9.53 x age [years]) + PAL x { (15.91 x weight [kg]) + (539.6 x height [m]) }, where PAL = 1 if sedentary, 1.11 if low active, 1.25 if active, and 1.48 if very active.
PAL = physical activity level
EER = Estimated Energy Requirements
His does interval training for 60 minutes per session at least 5 days a week that means he is active. PAL = 1.25
EER = 661.8 - (9.53 × 19) + 1.25×[(15.91 × 70.45) + (539.6×1.78)]
= 661.8 − 9.53(19) + 1.25((15.91×70.45)+(539.6×1.78))
= 3082.414375
EER = 3082kcal/day
Hence, his EER is about 3100 kcal/day.